Answer:
The researcher will conclude that there is a correlation between the number of hours worked out and the amount of pounds lost by people on the exercise program
Step-by-step explanation:
Here, we want to state what the conclusion of the researcher should be:
From the last part of the question, we can see that the test statistic is greater than the critical value
So what do we do in a case like this?
We can see that the researcher is trying to see if there is a correlation between hours worked out and the number of pounds lost over a specific period of time.
Now, let us form the null hypothesis;
The null hypothesis here H0 is that we do not have a correlation between number of hours spent working out and the amount of pounds lost
The alternative hypothesis here H1 is that there is a correlation between the number of hours spent working out and the amount of pounds lost
Since we have the value of the test statistic greater than the critical value, we reject the null hypothesis and accept the alternative hypothesis
So therefore, the researcher will conclude that there is a correlation between the number of hours worked out and the amount of pounds lost by people on the exercise program
I haven't learned antiderivitives yet but I can try to logic it
<span>First find f′ and then find f. f′′(x)=3x^3+6x^2−x+2, f′(1)=9, f(1)=−7.
we reverse chain rule
3x^3, we know that it was a 4th degree thing, and the coefient is 3, so
4*what=3?, answer is 3/4
3/4x^4
6x^2
we know it was x^3, and the coefient is now 6 so
3*what=6? what=2
2x^3
-1x, the power was 2 and coefient is now -1, so
2 times what=-1?, -1/2
-1/2x^2
2, that is from 2x
so
</span>
<span>3/4x^4+2x^3-1/2x^2+2x=f'(x)
test x=1
(3/4)(1)+2(1)-(1/2)(1)+2(1)=
3/4+2-2/4+2=
4 and 1/4 we need to get it to 9
4 and 1/4 +what=9
answer is 4 and 3/4
so we add that to the end since it will become 0 from derivitive
</span>
<span>f'(x)=3/4x^4+2x^3-1/2x^2+2x+4 and 3/4
now reverse drivitive again
3/4x^4
exponent is 5 and coefient is 3/4
5 times what=3/4? answer is 3/20
3/20x^5
2x^3
exponent should be 4 and coefient is 2
4 times what=2? answer is 1/2
1/2x^4
-1/2x^2
exponent should be 3 and coefient is -1/2
3 times what=-1/2? answer is -1/6
-1/6x^3
2x
exponent should be 2 and coefient is 2
2 times what=2? answer is 1
1x^2
4 and 3/4 turns to (4 and 3/4)x
</span>
<span>f(x)=3/20x^5+1/2x^4-1/6x^3+x^2+(4 and 3/4)x
try evaluating it for x=1
f(1)=(3/20)+(10/20)-(10/50)+1+(19/4)
f(1)=6 and 7/30
what do we add to get -7
-13 and 7/30
</span>
<span><span>f(x)=3/20x^5+1/2x^4-1/6x^3+x^2+(4 and 3/4)x-13 and 7/30
</span>
</span>ANSWER
<span>f'(x)=3/4x^4+2x^3-1/2x^2+2x+19/4
</span><span>f(x)=3/20x^5+1/2x^4-1/6x^3+x^2+19/4x-187/30</span>
15x<130+20, 15x<150 divided both sides by 15 ,the answer is 10
Answer:
40.265
Step-by-step explanation:
Divide 5 by 3 and continue dividing or mulitplying the numbers given
numbers on the top row: Mulityply
numbers on the bottom row: Divide
