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ankoles [38]
3 years ago
5

The point P(-5, -10) is rotated 90° counterclockwise about the origin. What are the coordinates of P'? *

Mathematics
2 answers:
VLD [36.1K]3 years ago
3 0
Nahhi pata hdydhdhhzyks gddykdyl >&;:
Law Incorporation [45]3 years ago
3 0

Answer:

P'(10, - 5 )

Step-by-step explanation:

Under a counterclockwise rotation about the origin of 90°

a point (x, y ) → (- y, x ) , then

P(- 5, - 10 ) → P'(10, - 5 )

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Answer:

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rewrite using trigonometry identities

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solve x by substitution

f(x) = 2 + sin(x) − 6sin²(x)

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= −2sinx(3sinx −2) − (3sinx−2)

= (3sinx −2)(−2sinx−1)

= −(3sinx −2)(2sinx+1)

f(x) = 2 + sin(x) − 6sin²(x) = 0

= −(3sinx −2)(2sinx+1) = 0

(3sinx −2) = 0 (2sinx+1) = 0

→sinx = 2/3 →sinx = −1/2

x = 41.81°, 138.19° x = 210°, 330°

(Please heart the answer if you find it helpful, it's a motivation for me to help more people)

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