The side lengths of quadrilateral are 21 inches; 11 inches; 11 inches; 7 inches.
<u>SOLUTION:</u>
Given, the perimeter of a quadrilateral (four-side polygon) is 50 inches.
Let the length of shortest side be n inches. The longest side is three times as long as the shortest side.
That is, length of largest side = 3n inches
The other two sides are equally long and are 4 inches longer than the shortest side.
Then, length of remaining two sides = 4 + n inches
We have to find the length of all four sides.
Now, we know that, perimeter = 50 inches

So, length of sides will be,

B and C
because the second number is a square of the first number
Make the denominator the same then add wholes then fractions and turn any extras into wholes then you have your answer 10 and 7/8
Translating that problem into an equation with x as a variable we get 3x + x +10 = 22. Combine like terms to get 4x + 10 = 22. Subtract 10 on both sides to get 4x = 12. Divide by 4 on both sides to get x = 3.
Now to plug in. The first number was represented by 3x. So substituting 3 for the x we get 3(3) = 9. And again for the second number represented by x+10, 3+10 = 13.
Your numbers are 9 and 13. To check just add them together. 13 + 9 is 22, I'll save ya the effort.