End behavior: f. As x -> 2, f(x) -> ∞; As x -> ∞, f(x) -> -∞
x-intercept: a. (3, 0)
Range: p. (-∞, ∞)
The range is the set of all possible y-values
Asymptote: x = 2
Transformation: l. right 2
with respect to the next parent function:
Domain: g. x > 2
The domain is the set of all possible x-values
Answer:
<h2><em><u>62</u></em><em><u>.</u></em><em><u>2</u></em></h2>
Step-by-step explanation:
4n × 2 + 43
<em>[</em><em>By</em><em> </em><em>putting</em><em> </em><em>the</em><em> </em><em>value</em><em> </em><em>of</em><em> </em><em>n</em><em> </em><em>=</em><em> </em><em>2</em><em>.</em><em>4</em><em>]</em>
= (4 ×2.4) × 2 + 43
= 9.6 × 2 + 43
= 19.2 + 43
= <em><u>62.2 (Ans)</u></em>
Complete Question
If minor arc AB measures 9 inches, what is the length of the radius of circle C? Where the radians is 0.75 radians
If necessary, round your answer to the nearest inch. 6 inches 12 inches 18 inches 24 inches
Answer:
12 inches
Step-by-step explanation:
The formula for Arc length =
Arc length = r θ
θ = 0.75
Arc length = 9 inches
Hence:
r = 9/ θ
r = 9/0.75
r = 12 inches
Only two integers i think, 7 and -7
