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storchak [24]
3 years ago
15

Mary is making some shirts for her school's drama department. The fabric store has yards of the fabric she wants in stock. But t

his quantity of fabric can make only shirts. What length of fabric does Mary need to buy if she wants to sew 2 shirts?
Mathematics
1 answer:
pashok25 [27]3 years ago
7 0

Answer: she will need 4 yards of fabric to make 2 shirts

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What is a construction?
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HELP!!! Show work!!!!!!
Misha Larkins [42]
A) x^5/6 ≠ 5√6, Because 5 is in numerator & 6 in denominator in exponential expression so it can be in direct expression.

It is False.

b) (16)^1/4 = 2.
It is False

c) a^2/7 + a^4/7 = a^2/7+4/7 = a^6/7
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d) Here, powers are not equivalent.
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In short, Your Answer is Option B

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Hope this helps!
7 0
3 years ago
Imagine a new pasture with grass growing on it. Every day after the seeds have germinated, the number of blades of grass in the
Arisa [49]

Answer:

It took 17 days for the pasture to be one-third covered in grass

Step-by-step explanation:

* Lets explain how to solve the problem

- The number of blades of grass is triple every day

- Consider that there are x blades in the first day

∵ The number of blades of grass is triple every day

∴ The next day the number of blades of grass will be 3x

∴ The formula to find the number of blades of grass after d days is

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- After 18 days, the entire pasture is completely covered in grass

∵ d = 18

∴ The number of blades of grass = x(3)^{18}

- We need to know the the number of days that took for the pasture

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∵ The number of blades of grass for 1/3 covered = (\frac{1}{3})x(3)^{18}

∴ (\frac{1}{3})x(3)^{18}=x(3)^{d}

- Remember  \frac{1}{3}=3^{-1}

∴ 3^{-1}x(3)^{18}=x(3)^{d}

- Remember we add the power of the same bases when we

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∴ x(3)^{-1+18}=x(3)^{d} ⇒ divide both sides by x

∴ (3)^{17}=(3)^{d}

- Remember if the two bases equal in the equation, then their

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∴ d = 17

* It took 17 days for the pasture to be one-third covered in grass

4 0
3 years ago
What function to use and how to use it
Lena [83]

That's the wrong right triangle to draw.  Reading the problem carefully we want this one, figure attached.

So we have the usual 30/60/90 triangle but not to scale.  The sides come in ratio 1:√3:2=x:100:hypotenuse.  So

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