Answer:
The page field is 8-bit wide, then the page size is 256 bytes.
Using the subdivision above, the first level page table points to 1024 2nd level page tables, each pointing to 256 3rd page tables, each containing 64 pages. The program's address space consists of 1024 pages, thus we need we need 16 third-level page tables. Therefore we need 16 entries in a 2nd level page table, and one entry in the first level page table. Therefore the size is: 1024 entries for the first table, 256 entries for the 2nd level page table, and 16 3rd level page table containing 64 entries each. Assuming 2 bytes per entry, the space required is 1024 * 2 + 256 * 2 (one second-level paget table) + 16 * 64 * 2 (16 third-level page tables) = 4608 bytes.
First, the stack, data and code segments are at addresses that require having 3 page tables entries active in the first level page table. For 64K, you need 256 pages, or 4 third-level page tables. For 600K, you need 2400 pages, or 38 third-level page tables and for 48K you need 192 pages or 3 third-level page tables. Assuming 2 bytes per entry, the space required is 1024 * 2 + 256 * 3 * 2 (3 second-level page tables) + 64 * (38+4+3)* 2 (38 third-level page tables for data segment, 4 for stack and 3 for code segment) = 9344 bytes.
Explanation:
16 E the answer
Answer:
All of the above.
Explanation:
Understanding that he must create a unique domain name for each client
Being able to work with HTML
Understanding of the World Wide Web and how hyperlinks work
All of these would be a critical skill Steve must have to be able to perform his job.
As for this problem about the part of the Internet, the most probable and the most likely to be the answer out of the options presented together with the problem is A. Interface.
<span>Interface would be the part of the Internet that you typically see. Interface is the widely known term used for GUI or Graphics User Interface. This covers about as to how you handle your desktop or computer. Basically, the moment the browser is opened, the interface appears. The other options are also arguable and that they might also pose the possibility of them being the correct answer taken as they are. Interface would cover them all and be the most likely answer.</span>
Answer:
See Explaination
Explanation:
/ Header files section
#include <iostream>
#include <fstream>
#include <iomanip>
#include <string>
#include <cmath>
using namespace std;
// start main function
int main()
{
// variables declaration
string fileName;
string lastName;
double score;
double total;
double grade;
string description;
// prompt the user to enter the input file name
cout << "Enter the input file name: ";
cin >> fileName;
// open the input file
ifstream infile;
infile.open(fileName);
// exit from the program if the input file does not open
if (!infile)
{
cout << fileName << " file cannot be opened!" << endl;
exit(1);
}
// repeat the loop for all students in the file
infile >> lastName;
while (infile)
{
infile >> score;
infile >> total;
// compute the grade
grade = score / total * 100;
// find the grade's description
if (grade > 90)
description = "Excellent";
else if (grade > 80)
description = "Well Done";
else if (grade > 70)
description = "Good";
else if (grade >= 60)
description = "Need Improvement";
else
description = "Fail";
// display the result of each student
cout << lastName << " " << setprecision(0) << fixed << round(grade) << "% " << setprecision(5) << fixed << (grade * 0.01) << " " << description << endl;;
infile >> lastName;
}
// close the input file
infile.close();
system("pause");
return 0;
} // end of main function
