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Brrunno [24]
3 years ago
9

Which ordered pair is a solution to the system of inequalities?

Mathematics
1 answer:
xxTIMURxx [149]3 years ago
7 0

Answer:

Option A

Step-by-step explanation:

System of the inequalities is,

y ≥ 2x

y < x + 4

By satisfying these inequalities with the points given in the options we can get the answer.

Option (A). (2, 5)

y ≥ 2x

5 ≥ 2(2)

5 ≥ 4

True.

y < x + 4

5 < 2 + 4

5 < 6

True

Therefore, Option (1) is the answer.

Option (B) (1, 6)

y ≥ 2x

6 ≥ 2(1)

6 ≥ 2  

True.

y < x + 4

6 < 1 + 4

6 < 5

False.

Therefore, it's not the solution.

Option (C) (2, 3)

y ≥ 2x

3 ≥ 2(2)

3 ≥ 4

False.

y < x + 4

4 < 2 + 4

4 < 6

True.

Therefore, It's not the solution.

Option (D) (1, 5)

y ≥ 2x

5 ≥ 2(1)

5 ≥ 4

True.

y < x + 4

5 < 1 + 4

5 < 5

False.

Therefore, It's not the solution.

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The population of a local species of flies can be found using an infinite geometric series where a1 = 940 and the common ratio i
skad [1K]


A geometric series is the sum of the terms of a geometric sequence of  the form a, ar, ar^{2},  ar^{3},..., 
where r is the common ratio, and a≠0 is the first term.

That is, the series is  a+ar+ar^{2}+ar^{3},...

In sigma notation, the series is written as:

∞
∑  a r^{k} 
k=0
--------------------------------------------------------------------------------------------------

The geometric series of the form
∞
∑  a r^{k}, converges to \frac{a}{1-r} if |r|<1
k=0

and diverges otherwise.
--------------------------------------------------------------------------------------------------

in our problem, a , the first term is equal to 940, and the common ratio is |1/5|<1, 

thus the series converges to:
\frac{a}{1-r}=\frac{940}{1-1/5}=\frac{940}{4/5}=752


Answer: 

∞          
∑  940 (1/5)^{k}=752   ( the upper limit of the population is 752)
k=0

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3 years ago
Simplify: LaTeX: (4a + 6b)^2.
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Answer:

4 (2a+3b)^2

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take 4 common factor

4 (4a^2 + 12ab + 9b^2) =  4 (2a+3b)^2

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