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Brrunno [24]
3 years ago
9

Which ordered pair is a solution to the system of inequalities?

Mathematics
1 answer:
xxTIMURxx [149]3 years ago
7 0

Answer:

Option A

Step-by-step explanation:

System of the inequalities is,

y ≥ 2x

y < x + 4

By satisfying these inequalities with the points given in the options we can get the answer.

Option (A). (2, 5)

y ≥ 2x

5 ≥ 2(2)

5 ≥ 4

True.

y < x + 4

5 < 2 + 4

5 < 6

True

Therefore, Option (1) is the answer.

Option (B) (1, 6)

y ≥ 2x

6 ≥ 2(1)

6 ≥ 2  

True.

y < x + 4

6 < 1 + 4

6 < 5

False.

Therefore, it's not the solution.

Option (C) (2, 3)

y ≥ 2x

3 ≥ 2(2)

3 ≥ 4

False.

y < x + 4

4 < 2 + 4

4 < 6

True.

Therefore, It's not the solution.

Option (D) (1, 5)

y ≥ 2x

5 ≥ 2(1)

5 ≥ 4

True.

y < x + 4

5 < 1 + 4

5 < 5

False.

Therefore, It's not the solution.

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Answer:

1. 43/36

2. 1/2

Step-by-step explanation:

1. 7/9 + 5/12

= LCM of 9 and 12 is 36

= 28/36 + 15/12

= (28 + 15) / 36

= 43/36

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Each morning, Hungry Harry eats some eggs. On any given morning, the number of eggs he eats is equally likely to be 1, 2, 3, 4,
mamaluj [8]

Answer:

Mean = 35

Variance = 291.7

Step-by-step explanation:

Data provided in the question:

X : 1, 2, 3, 4, 5, 6

All the data are independent

Thus,

The mean for this case will be given as:

Mean, E[X] = \frac{\textup{Sum of all the observations}}{\textup{Total number of observations}}

or

 E[X] = \frac{\textup{1+2+3+4+5+6}}{\textup{6}}

or

E[X] = 3.5

For 10 days, Mean = 3.5 × 10 = 35

And,

variance = E[X²] - ( E[X] )²

Now, for this case of independent value,

E[X²] = \frac{1^2+2^2+3^2+4^2+5^2+6^2}{\textup{6}}

or

E[X²] = \frac{1+4+9+16+25+36}{\textup{6}}

or

E[X²] = \frac{91}{\textup{6}}

or

E[X²] = 15.167

Therefore,

variance = E[X²] - ( E[X] )²

or

variance = 15.167 - 3.5²

or

Variance = 2.917

For 10 days = Variance × Days²

= 2.917 × 10²

= 291.7

3 0
3 years ago
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