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3 years ago

ILL MARK AS BRAINLIST

Mathematics

1 answer:

Mazyrski [523]3 years ago

5 0

Answer:

–3/5

please.mark as brainliest

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A company charges $211.25 for 5 trees and 15 shrubs. The company charges 15.25 more for a tree than a shrub. How much does each

postnew [5]

The answer is $1.96 I hope I could help?

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3 years ago

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Find the square. (1/4A + 1/4B)^2<br><br> a) 1/16A^2 + 1/8AB + 1/16B^2<br> b) 1/4A^2 + 1/8AB + 1/4B^2

alisha [4.7K]

$(a + b)^2 = a^2 + 2ab + b^2$

$(\dfrac{1}{4}A + \dfrac{1}{4}B)^2 =$

$= \dfrac{1}{16}A^2 + \dfrac{1}{8}AB + \dfrac{1}{16}B^2$

Answer: A.

Another way to solve by factoring 1/4.

$(\dfrac{1}{4}A + \dfrac{1}{4}B)^2 =$

$= [\dfrac{1}{4}(A + B)]^2$

$= (\dfrac{1}{4})^2(A + B)^2$

$= \dfrac{1}{16}(A^2 + 2AB + B^2)$

$= \dfrac{1}{16}A^2 + \dfrac{1}{16}2AB + \dfrac{1}{16}B)^2$

$= \dfrac{1}{16}A^2 + \dfrac{1}{8}AB + \dfrac{1}{16}B)^2$

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4 years ago

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The number of phone calls that Actuary Ben receives each day has a Poisson distribution with mean 0.1 during each weekday and me

Dovator [93]

Answer:

There is a 0.73% probability that Ben receives a total of 2 phone calls in a week.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

$e = 2.71828$ is the Euler number

$\mu$ is the mean in the given time interval.

The problem states that:

The number of phone calls that Actuary Ben receives each day has a Poisson distribution with mean 0.1 during each weekday and mean 0.2 each day during the weekend.

To find the mean during the time interval, we have to find the weighed mean of calls he receives per day.

There are 5 weekdays, with a mean of 0.1 calls per day.

The weekend is 2 days long, with a mean of 0.2 calls per day.

So:

$\mu = \frac{5(0.1) + 2(0.2)}{7} = 0.1286$

If today is Monday, what is the probability that Ben receives a total of 2 phone calls in a week?

This is $P(X = 2)$ . So:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 2) = \frac{e^{-0.1286}*0.1286^{2}}{(2)!} = 0.0073$

There is a 0.73% probability that Ben receives a total of 2 phone calls in a week.

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3 years ago

Whats the answer for this

Oxana [17]

Answer:

a) Angle X = 108°

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as AD is parallel to EH both the angles are equal

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2 years ago

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the times in seconds it took 6 finalists to run a 100 meter dash are 12.5 12.4 12.4 12.3 12.6 and 12.4. mr brown picks out the t

yulyashka [42]

Answer:

The times in seconds it took 6 finalists to run a 100 meter dash are 12.5 12.4 12.4 12.3 12.6 and 12.4. Mr. Brown picks out the time that appears the most to find the <u>mode</u> he arranges the times in increasing order and picks the middle value to find the <u>median</u>

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3 years ago

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