1. First of all arrange the data set in either ascending or descending order.
12, 19, 24, 26, 31, 38, 53. N = 7 (number of data items)
Median position = 1/2(N + 1)th item = 1/2(7 + 1)th item = 1/2(8)th item = 4th item = 26
First quatile = 1/4(N + 1)th item = 1/4(7 + 1)th item = 1/4(8)th item = 2nd item = 19
Third quatile = 3/4(N + 1)th item = 3/4(7 + 1)th item = 3/4(8)th item = 6th item = 38
Interquatile range = Third quartile - first quatile = 38 - 19 = 19
Answer:
63 degrees
Step-by-step explanation:
180 = 117 = 63
Answer:
Step-by-step explanation:
From the first receipt:
2 pounds of grapes + 4 pounds of oranges = 10.70 which, in an algebraic equation, looks like this:
2g + 4o = 10.70
From the second receipt:
3 pounds of grapes + 2 pounds of oranges = 9.65 which, in an algebraic equation, looks like this:
3g + 2o = 9.65
Putting those together into a system and solving using the elimination method:
2g + 4o = 10.7
3g + 2o = 9.65
I am going to eliminate the oranges first since it's easier to do that. I will multiply the second equation by -2 to get a new system:
2g + 4o = 10.7
-6g - 4o = -19.3
As you can see, the oranges are eliminated because 4o - 4o = 0o. That leaves us with only the grapes:
-4g = -8.6 so
g = 2.15
Grapes cost $2.15 per pound. Now sub that into either one of the original equations to solve for the cost per pound of oranges:
2(2.15) + 4o = 10.7 and
4.3 + 4o = 10.7 and
4o = 6.4 so
o = 1.60
Oranges cost $1.60 per pound. That is choice D from your list.
The answer could be D- pq. It's not from the center of the circle.
Answer:
$7200 in the fund rose 6% n $2800 in the fund rose 9%
Step-by-step explanation:
let x be the amount in the fund rose 6%
gain in one year=x*6%=0.06x
total amount is 10000
so amount in the fund rose 9% = 10000-x
gain in one year=(10000-x)*9%=900-0.09x
total gain=0.06x+900-0.09x=900-0.03x
=684
900-684=0.03x
0.03x=216
x=7200
the other fund amount=10000-7200=2800
