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kicyunya [14]
3 years ago
11

A fair number cube is rolled. What is the probability that a number greater than 2 is rolled

Mathematics
2 answers:
exis [7]3 years ago
3 0

Answer:

2/3

Step-by-step explanation:

Ah, I see. A 1-6 die.

Probability of one number = 1/6

2 numbers? = 2/6

6/6-2/6=4/6

4/6=2/3

Umnica [9.8K]3 years ago
3 0

\huge{\boxed{\frac{2}{3}}}

There are 4 numbers on a number cube that are greater than 2. They are 3, 4, 5, 6.

Write this as a fraction. \frac{\text{4 favorable outcomes}}{\text{6 total outcomes}}

Divide both the numerator and denominator by 2 to simplify. \boxed{\frac{2}{3}}

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When the chef turned the new freezer on, the temperature on the internal thermometer was 2 °C.
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The product of two consecutive positive integers is 132. What are the integers?
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Answer:

The integers are 11 and 12

Step-by-step explanation:

11 and 12 are consecutive positive integers, and 11 x 12 = 132.

5 0
3 years ago
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Read 2 more answers
Write the name of a vector with a magnitude of 13 in algebraic form that is perpendicular to the line 7x + 2y =6. Please explain
Kamila [148]

Answer:

The vector is < 91 / sqrt(53),26 / sqrt(53)>  or <-91 / sqrt(53),-26 / sqrt(53)>

Step-by-step explanation:

7x + 2y =6

We need to find the slope so we solve for y

Subtract 7x from each side

7x -7x+ 2y =-7x+6

2y = -7x +6

Divide by 2

2y/2 = -7x /2 + 6/2

y = -7/2 x +3

The slope is -7/2

We want it perpendicular so the slope must be the negative reciprocal

m = -(-2/7)

   = 2/7

Vectors are written in the form  

v = <  x, y>

slope = change in y over change in x

So y/x = 2/7  or 7y =2x

Now we worry about the magnitude

Magnitude is sqrt(x^2 + y^2) and it equals 13

sqrt(x^2 + y^2)= 13

square both sides

x^2 + y^2 = 169

We have 2 equations and 2 unknowns

y = (2/7x)

x^2 +(2/7x) ^2 = 169

x^2 +4/49 x^2 =169

49/49 x^2 +4/49 x^2 = 169

53/49  x^2 = 169

x^2 = 169 *49/53

Take the square root of each side

x = ±91 / sqrt(53)

y =  (2/7x)

   = 2/7 * ±91 / sqrt(53)

   = ±26 / sqrt(53)

The vector is < 91 / sqrt(53),26 / sqrt(53)>  or <-91 / sqrt(53),-26 / sqrt(53)>

6 0
3 years ago
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