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kicyunya [14]
3 years ago
11

A fair number cube is rolled. What is the probability that a number greater than 2 is rolled

Mathematics
2 answers:
exis [7]3 years ago
3 0

Answer:

2/3

Step-by-step explanation:

Ah, I see. A 1-6 die.

Probability of one number = 1/6

2 numbers? = 2/6

6/6-2/6=4/6

4/6=2/3

Umnica [9.8K]3 years ago
3 0

\huge{\boxed{\frac{2}{3}}}

There are 4 numbers on a number cube that are greater than 2. They are 3, 4, 5, 6.

Write this as a fraction. \frac{\text{4 favorable outcomes}}{\text{6 total outcomes}}

Divide both the numerator and denominator by 2 to simplify. \boxed{\frac{2}{3}}

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Naddik [55]

Answer:  530.66 units²

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3 0
3 years ago
Orbet used 24 square tiles to make a rectangle. The perimeter of the rectangle is 20 units. What would be the perimeters of the
Dmitriy789 [7]

Answer:

The perimeter of other rectangles are 50, 28, 22 units

The area of all possible rectangles are same and equals to 24 unit²

Step-by-step explanation:

Given - Orbet used 24 square tiles to make a rectangle. The perimeter of the rectangle is 20 units.

To find -  What would be the perimeters of the other rectangles Orbet could make using only these 24 tiles? How do the areas of the rectangles compare?

Proof -

We know that

Are of Rectangle = Length × Breadth

And Perimeter of Rectangle = 2 (Length + Breadth )

Now,

Given that,

Orbet used 24 square tiles

And perimeter of the rectangle made = 20

So,

Possible Length of rectangle = 6

Possible breadth of Rectangle = 4

Or Vice-versa.

Total number of Rectangles possible = 4

Possibilities are -  1 × 24, 2 × 12, 3 × 8, 4 × 6

Case I :

Length of rectangle = 1

Breadth of rectangle = 24

∴ Perimeter of rectangle = 2(1 + 24) = 2(25) = 50 units

Area of rectangle = 1 × 24 = 24 unit²

Case II :

Length of rectangle = 2

Breadth of rectangle = 12

∴ Perimeter of rectangle = 2(2 + 12) = 2(14) = 28 units

Area of rectangle = 2 × 12 = 24 unit²

Case III :

Length of rectangle = 3

Breadth of rectangle = 8

∴ Perimeter of rectangle = 2(3 + 8) = 2(11) = 22 units

Area of rectangle = 3 × 8 = 24 unit²

Case IV :

Length of rectangle = 4

Breadth of rectangle = 6

∴ Perimeter of rectangle = 2(4 + 6) = 2(10) = 20 units

Area of rectangle = 4 × 6 = 24 unit²

∴ we get

The perimeter of other rectangles are 50, 28, 22 units

The area of all possible rectangles are same and equals to 24 unit²

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3 years ago
Θ is an acute angle. Find the value of θ in radians.
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7 0
3 years ago
14+4k=2−2k solve for k
n200080 [17]
14+4k=2-2k
4k+2k=2-14
6k=-12
k=-12/6
k=-2


sorry if I'm wrong
7 0
3 years ago
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