Step-by-step explanation:
The required sum
=(1+2+3+...+199)−(3+6+9+...+198)−(5+10+15+...+195)+(15+30+45+...+195)
=2199(1+199)−266(3+198)−239(5+195)+213(15+195)
=199×100−33×201−39×100+13×105=10732
Answer:
Step-by-step explanation:
![Volume\:of\:cube:V=a^{3} \:(a\:is\:the\:length\:of\:each\:edge)\\\Leftrightarrow a=\sqrt[3]{V} \Leftrightarrow a=\sqrt[3]{729} =9](https://tex.z-dn.net/?f=Volume%5C%3Aof%5C%3Acube%3AV%3Da%5E%7B3%7D%20%5C%3A%28a%5C%3Ais%5C%3Athe%5C%3Alength%5C%3Aof%5C%3Aeach%5C%3Aedge%29%5C%5C%5CLeftrightarrow%20a%3D%5Csqrt%5B3%5D%7BV%7D%20%5CLeftrightarrow%20a%3D%5Csqrt%5B3%5D%7B729%7D%20%3D9)
Given: 16cm long, 6cm wide, 23 cm tall
Asked: volume of the box
Formula: V=LxWxH
Solution: V = 16x6x23 = n
Answer: 2,208 cm³ volume of the box
0.52 x 0.24 means "about a half times 0.24". Given the multiple choice answers, the correct answer is therefore 0.1224 (since this is the only one smaller than 0.24).
Proof:
0.50 × 0.24 = 0.12
0.01 × 0.24 = 0.0024
And therefore 0.51 × 0.24 = 0.12 + 0.0024 = 0.1224
Http://lbcsd.innersync.com/sites/jhayes/documents/U1M3Gr6pg.49-502015JHayes.pdf
