Answer:
$450
Step-by-step explanation:
20 goes into 100 five times.
90*5=450
Her paycheck was $450.
Answer:
y = 9.8995
Step-by-step explanation:
This question requires the use of basic trigonometry.
In this problem, we know one of the sides and two of the angles.
Since one of the angles is 45 degrees and the sum of all internal angles of a triangle is 180 degrees, the other angle can only be 45 degrees, making this an isosceles triangle - that is, the length of the other leg, x, is also 7.
You could use the soh cah toa mnemonic to figure it out, but here just using the a^2 + b^2 = c^2 should be sufficient since we know both legs of the triangle.
7^2 + 7^2 = 98, and the square root of 98 gives you about 9.8995, which sounds about right for this situation.
Hope this helped!
Answer:
493.582 nearest hundredth
=500
To answer the problem above, take note that for negative numbers, the bigger the numerical equivalent of the number without considering the sign, the smaller its value is. From the given above, the order from least to greatest is: -3930, -0.7, 9.73, and 92.
Answer:
D. 4(2x² + 4x - 6); 130.0 inches
Step-by-step explanation:
Margot is sewing a ribbon on a seam along the perimeter of a square pillow. The side length of the pillow is 2x²+1 inches. She plans to make a similar pillow, including the ribbon, whose side length is 4x−7 inches. What expression can be used for the length of ribbon that she needs for both pillows, and what is the length if x = 3.5?
2x2+4x−6; 22.0 inches
2x2+4x−6; 32.5 inches
4(2x2+4x−6;) 88.0 inches
4(2x2+4x−6;) 130.0 inches
Perimeter of a square = 4 * side length
1- First square pillow
length = 2x²+1 in
Perimeter of first pillow = 4 * (2x²+1) in
Second square pillow
length = 4x-7 in
Perimeter of second pillow = 4(4x-7) in
Total ribbon length required = perimeter of first square pillow + perimeter of second square pillow
Total ribbon length required = 4(2x²+1) + 4(4x-7)
Factorise
4 is the common factor
=4(2x²+1)+(4x-7)
=4(2x²+1+4x-7)
=4(2x²+4x-6)
Total ribbon length required=4(2x²+4x-6)
If x=3.5
Total ribbon length required=4(2x²+4x-6)
=4{2(3.5)²+4(3.5)-6}
=4{2(12.25)+14-6)
=4(24.5+14-6)
=4(32.5)
=130.0 inches
