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3 years ago

HELP PLSS I HAVE 10 minutes

Mathematics

1 answer:

omeli [17]3 years ago

4 0

Answer:

h≈1.43

Step-by-step explanation:

Simply ,Square the radius, and then divide the radius squared into the tripled volume. For this example, the radius is 2. The square of 2 is 4, and 300 divided by 4 is 75. Divide the amount calculated in Step 2 by pi, which is an unending math constant that begins 3.14, to calculate the cone's height.

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At midnight, the outside temperature was -12.3 degrees. By 6:00 AM the outside tempature had dropped 6.8 degrees.

choli [55]

It was -19.1 degrees

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3 years ago

Ewans flight is schheduled to travel 1,750 in 3.5 hours . at what rate does it travel per hour

Karo-lina-s [1.5K]

Answer:

It travel at the rate of 500 miles per hour.

Step-by-step explanation:

Given:

Ewans flight is scheduled to travel 1,750 miles in 3.5 hours.

Now, to find the rate it travel per hour.

Distance = 1,750 miles.

Time = 3.5 hours.

So, to get the rate we put formula:

$Speed=\frac{distance}{time}$

$Speed=\frac{1750\ miles}{3.5\ hours}$

$Speed=500\ miles\ per\ hour$

Therefore, it travel at the rate of 500 miles per hour.

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3 years ago

Malik collects rare stamps and has a total of 96 stamps. He has 24 more domestic stamps than foreign stamps. Let d represent the

Dvinal [7]

Answer:

Domestic Stamps: 60

Foreign Stamps: 36

Step-by-step explanation:

96 - 24 = 72

72 ÷ 2 = 36

36 + 24 = 60

d - f = 24

60 - 36 = 24

24 = 24

d + f = 96

60 + 36 = 96

96 = 96

6 0

3 years ago

Read 2 more answers

Jackson flipped a coin ten time. He flipped heads 4 times and tails 6 times. What is the experimental probability that Jackson w

barxatty [35]

Answer:

Step-by-step explanation:

Given that,

Outcomes Heads= 4heads and

Outcomes Tails= 6tails

Total outcome of events n=10

Probability of head in is first throw is, the is the outcome of head divide by the total possible outcomes

P(Head in first throw)=4/10

P(H)=2/5

P(H) = 0.4

P(H) =40%

7 0

3 years ago

Read 2 more answers

A builder wants to build the bridge whose cross section is shown in the diagram. Two companies offer simple bids on building the

leva [86]

The length of the bridge is the distance from the beginning to the end.

The distance b between each beam is 9ft.

Let:

$I \to$ I-Beam

$d_I \to$ distance between I beam and the bridge

$b \to$ distance between each I beam

Given that:

$I = \frac 34 ft\\$

$d_I = 3 ft$

$Length = 55ft\ 6in$ --- length of the bridge

From the diagram (see attachment), there are: 6 I-beams.

So, the length of the 6 I-beams is:

$L_1 = 6 \times I$

$L_1 = 6 \times \frac 34$

$L_1 = \frac {18}4$

$L_1 = 4.5ft$

There are 2 I-beams beside the bridge

So, the distance between the 2 I-beams and the bridge is:

$d_1 =2 \times d_I$

$d_1 =2 \times 3ft$

$d_1 =6ft$

There are 5 spaces between the I-beams

So, the length of the total spaces is:

$L_2 = 5 \times b$

$L_2 = 5b$

The total length is:

$Length = L_1 + d_1 + L_2$

So, we have:

$4.5ft + 6ft + 5b = 55ft\ 6in$

Collect like terms

$5b = 55ft\ 6in - 4.5ft - 6ft$

$5b = 44.5ft\ 6in$

Convert inches to feet

$5b = 44.5ft\ + \frac{6}{12}ft$

$5b = 44.5ft\ + 0.5ft$

$5b = 45ft$

Divide both sides by 5

$b = 9ft$

Hence, the distance (b) between each beam is 9ft.