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2 years ago

Plz help me with this and save me!!!!!!!1

Mathematics

2 answers:

maxonik [38]2 years ago

8 0

Answer:

Step-by-step explanation:

"at most" meaning less than or equal to

Oliga [24]2 years ago

6 0

Answer:

ITS THE THIRD ONE!!!!! I AM VERY VERY CERTAIN!!!

x <u><</u> 2

Brainliest would be great! Good luck on the test.

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9> -2m + 2 - 3

Tanya [424]

Answer:

Step-by-step explanation:

Given

9 > - 2m + 2 - 3, that is

9 > - 2m - 1 ( add 1 to both sides )

10 > - 2m

Divide both sides by - 2, reversing the symbol as a result if dividing by a negative quantity.

- 5 < m , thus

m > - 5 → A

6 0

2 years ago

Read 2 more answers

The surface area of this rectangular prism of 5m,5m,4m

Blizzard [7]

Answer:

130 m^2 (meters squared)

4 0

2 years ago

How to find imaginary zeros anf real zeros of F(x)=-4x^5-8x^3+12x

Fofino [41]

Answer:

$x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}$

Step-by-step explanation:

We are given the function:

$f(x)=-4x^5-8x^3+12x$

And we want to finds its zeros.

Therefore:

$0=-4x^5-8x^3+12x$

Firstly, we can divide everything by -4:

$0=x^5+2x^3-3x$

Factor out an x:

$0=x(x^4+2x^2-3)$

This is in quadratic form. For simplicity, we can let:

$u=x^2$

Then by substitution:

$0=x(u^2+2u-3)$

Factor:

$0=x(u+3)(u-1)$

Substitute back:

$0=x(x^2+3)(x^2-1)$

By the Zero Product Property:

$x=0\text{ and } x^2+3=0\text{ and } x^2-1=0$

Solving for each case:

$x=0\text{ and } x=\pm\sqrt{-3}\text{ and } x=\pm\sqrt{1}$

Therefore, our real and complex zeros are:

$x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}$

4 0

2 years ago

The figure below shows three uniform objects: a rod with m1 = 7.00 kg, a right triangle with m2 = 3.70 kg, and a square with m3

navik [9.2K]

The answer is

G = [m1(veca1a2) + m2 (veca3a4) + m3veca5a6)] / (m1 + m2 + m3)

G= m1x5 + m2 x 4sqrt (2) + m3x 3sqrt (2) / 16 = 35 +4 x 3.7x sqrt (2) + 5.3 x3 4sqrt (2) / 16 =35 + 36<span> sqrt (2) / 16
G = 53.09
LOOK AT THE IMAGE

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6 0

2 years ago

If the original lengths are multiplied by 2, what are the new coordinates?

Bad White [126]

Answer:

Find an answer to your question If the original lengths are multiplied by 2, what is the new coordinate of point A? Assume that the point at (0,0) ...

Step-by-step explanation:

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3 years ago