A bag of marbles has 6 red marbles and 7 green marbles in it. What is the percent probability of pulling a green marble out of t
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g(x) = (1/4)x^2 . correct option C) .
<u>Step-by-step explanation:</u>
Here we have , and we need to find g(x) from the graph . Let's find out:
We have , . From the graph we can see that g(x) is passing through point (2,1 ) . Let's substitute this point in all of the four options !
A . g(x) = (1/4x)^2
Putting (2,1) in equation g(x) = (x/4)^2 , we get :
⇒
⇒
Hence , wrong equation !
B . g(x) = 4x^2
Putting (2,1) in equation g(x) = 4x^2 , we get :
⇒
⇒
Hence , wrong equation !
C . g(x) = (1/4)x^2
Putting (2,1) in equation g(x) = (1/4)x^2 , we get :
⇒
⇒
Hence , right equation !
D . g(x) = (1/2)x^2
Putting (2,1) in equation g(x) = (1/2)x^2 , we get :
⇒
⇒
Hence , wrong equation !
Therefore , g(x) = (1/4)x^2 . correct option C) .
Answer:
y-intercept: 10
concavity: function opens up
min/max: min
Step-by-step explanation:
1.) The definition of a y-intercept is what the resulting value of a function is when x is equal to 0.
Therefore, if the function's equation is given, to find y-intercept simply plug in 0 for the x-values:
y intercept ( f(0) )= 10
2.) In order to find concavity (whether a function opens up or down) of a quadratic function, you can simply find the sign associated with the x^2 value. Since 2x^2 is positive, the concavity is positive. This is basically possible, since it is identifying any reflections affecting the y-values / horizontal reflections.
3.) In order to find whether a quadratic function has a maximum or minimum, you can use the concavity of the function. The idea is that if the function opens downwards, the vertex would be at the very top, resulting in a maximum. If a function was open upwards, the vertex would be at the very bottom, meaning there is a minimum. Like the concavity, if the value associated with x^2 is positive, there is a minimum. If it is negative, there is a maximum. Since 2x^2 is positive, the function has a minimum.