Michael took the return trip at a velocity 33.75 miles per hour.
<h3>How fast did Michael drive in his return trip?</h3>
Let suppose that Michael drove in <em>straight line</em> road and at <em>constant</em> velocity. Therefore, the speed of the vehicle (v), in miles per hour, can be defined as distance traveled by the vehicle (d), in miles, divided by travel time (t), in hours.
First trip
45 = s / 3 (1)
Second trip
v = s / 4 (2)
By (1) and (2):
45 · 3 = 4 · v
v = 33.75 mi / h
Michael took the return trip at a velocity 33.75 miles per hour.
To learn more on velocities: brainly.com/question/18084516
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<u><em>Answer:</em></u>
575% as a mixed number is 
<u><em>Explanation:</em></u>
575% is equivalent to 
which is equal to 5.75
5.75 = 5 + 0.75
0.75 can be written as 
. This value can be simplified by dividing both the numerator and the denominator by 25. This would give us 
<u>Back to our number:</u>
Hope this helps :)
In this question they've given us the formula and they just want us to plug in the numbers and get the value.
P is the original value, P=$600
r is the depreciation rate, r=10%=0.1
t is the time in years, t=2
Answer: $486
Answer:
5.) 0.134 kg.
6.) 6.15 km.
7.) 5.9 kg.
Step-by-step explanation:
5.) 0.37 - 0.236 = 0.134
6.) 9.71 - 3.56 = 6.15
7.) 1.7 + 4.2 = 5.9
8
A. Delivery is $20. One cord is $120.
B. 1 1/2 cord costs $200. ($180 for the cord and $20 for the delivery)
(I can’t see the full problem for 9)
