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telo118 [61]
2 years ago
8

Ayudaa

Mathematics
1 answer:
ArbitrLikvidat [17]2 years ago
6 0
The coordinates are 68276528
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Which value of x makes this equation true? –5(– 20 ) = 35 <br>A. -11<br>B. -3 <br>C. 13 <br>D. 27​
kirza4 [7]

Answer:

c

Step-by-step explanation:

its right

3 0
2 years ago
Read 2 more answers
Determine the circumference of<br>a circle with diameter 28 cm. Show your work​
gulaghasi [49]

Answer:

Step-by-step explanation:

Diameter = 28 cm

therefore, radius = 28 / 2 = 14 cm

Circumference = 2 π r

= 2 × 22 / 7 × 14

= <u><em>88 cm</em></u>

Hope this helps

plz mark as brainliest!!!!!

8 0
3 years ago
Read 2 more answers
Brainliest fir CORRECT answer ​
viktelen [127]

Answer:

y ≈ 5.2

Step-by-step explanation:

∠ F = 180° - (42 + 48)° ← sum of angles in a triangle

∠ F = 180° - 90° = 90°

Thus Δ DEF is right at F

Using the sine ratio in the right triangle

sin48° = \frac{opposite}{hypotenuse} = \frac{DF}{DE} = \frac{y}{7} ( multiply both sides by 7 )

7 × sin48° = y , then

y ≈ 5.2 ( to the nearest tenth )

4 0
2 years ago
The school that Kathryn goes to is selling tickets to the annual talent show. On the first day of ticket sales the school sold 1
Kobotan [32]

Answer:

Step-by-step explanation:

a+s=14

a=14-s

a+8s=56, using a from above in this equation gives

14-s+8s=56

14+7s=56

7s=42

s=6

a=14-s

a=14-6=8

So student tickets cost $6 and adult tickets cost $8.

5 0
2 years ago
what is te discontinuity of the function f(x) = the quantity of x squared plus 6x plus 8 all over x plus 4?
seropon [69]

Answer:

A hole at x=-4.

Step-by-step explanation:

This is a fraction so we have to worry about division by zero.

The only time we will be dividing by 0 is when x+4 is 0.

Solving the equation

x+4=0 for x:

Subtract 4 on both sides:

x=-4

So there is either a vertical asymptote or a hole at x=-4.

These are the kinds of discontinuities we can have for a rational function.

If there is a hole at x=-4, then x=-4 will make the top zero and can be cancelled out after simplification.

If is is a vertical asymptote, x=-4 will make the top NOT zero.

Let's see what -4 for x in x^2+6x+8 gives us:

(-4)^2+6(-4)+8

16+-24+8

-8+8

0

Top and bottom are 0 when x=-4.

Let's see what happens after simplication.

We are going to factor a^2+bx+c if factorable by finding two numbers that multiply to be c and add up to be b.

So what 2 numbers together multiply to be 8 and add up to be 6.

I hoped you said 4 and 2 because (4)(2)=8 where 4+2=6.

\frac{x^2+6x+8}{x+4}=\frac{(x+4)(x+2)}{x+4}=x+2

We we able to cancel out that factor that was giving us x=-4 is a zero.  

Therefore there is a hole at x=-4.

7 0
3 years ago
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