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3 years ago

A triangular prism and two nets are shown:

Mathematics

1 answer:

lilavasa [31]3 years ago

4 0

Answer:

Net for the prism will have 3 rectangles with dimensions 5 by 15, 12 by 15 , and 13 by 15, and 2 triangles with legs 5 inches and 12 inches.

The correct net is net a.

Surface area = sum of areas of the three rectangles and sum of the two triangles.

SA = (5 x 15) + (12 x 15) + (13 x 15) + (5 x 12) = 75 + 180 + 195 + 60 = 510 square inches.

Step-by-step explanation:

Hope this helped

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Please answer fast however answer i will make brainilest

Marizza181 [45]

Answer:

Step-by-step explanation:

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3 years ago

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What are the values of a and b?

Helen [10]

A is 6 because so is the side across from it

And B is 8 because it the same size just flip it

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3 years ago

An automobile company wants to determine the average amount of time it takes a machine to assemble a car. A sample of 40 times y

aksik [14]

Answer:

A 98% confidence interval for the mean assembly time is [21.34, 26.49] .

Step-by-step explanation:

We are given that a sample of 40 times yielded an average time of 23.92 minutes, with a sample standard deviation of 6.72 minutes.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample average time = 23.92 minutes

s = sample standard deviation = 6.72 minutes

n = sample of times = 40

$\mu$ = population mean assembly time

Here for constructing a 98% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, a 98% confidence interval for the population mean, $\mu$ is;

P(-2.426 < $t_3_9$ < 2.426) = 0.98 {As the critical value of z at 1% level

of significance are -2.426 & 2.426}

P(-2.426 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.426) = 0.98

P( $-2.426 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.426 \times {\frac{s}{\sqrt{n} } }$ ) = 0.98

P( $\bar X-2.426 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.426 \times {\frac{s}{\sqrt{n} } }$ ) = 0.98

98% confidence interval for $\mu$ = [ $\bar X-2.426 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.426 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $23.92-2.426 \times {\frac{6.72}{\sqrt{40} } }$ , $23.92+2.426 \times {\frac{6.72}{\sqrt{40} } }$ ]

= [21.34, 26.49]

Therefore, a 98% confidence interval for the mean assembly time is [21.34, 26.49] .

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3 years ago

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Answer:

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Step-by-step explanation:

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4 years ago

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Gemiola [76]

She originally started with 23.

We can tell this by working the equation backwards. Since she has 5 left and she had just given half to her brother, we know she had 10 a moment ago.

Before that, Mary had eaten a cookie. So we add 1 to the total and now have 11.

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