Answer:
U =35.5
Step-by-step explanation:
Since this is a right angle, we can use trig functions
tan theta = opp/ adj
tan U = 5/7
Take the inverse of each side
tan ^-1 tan U = tan ^-1 (5/7)
U = 35.53767779
Round to the nearest tenth
U =35.5
Answer:
B
Step-by-step explanation:
16 x 3/2 = 24
24 x 3/2 = 36
36 x 3/2 = 54
Answer:
N(2,3)
Step-by-step explanation:
According to the Question,
- Given that, In the triangle ABC. M is the midpoint of AB and N is the midpoint of CM And A(-1, 3), B(7-3) and C(1,6).
- Thus, For coordinates of N. first We have to find the Coordinate of M(x,y). As Given M is the Midpoint of A(-1, 3) and B(7-3).
Thus, M(x,y) = (-1+7)/2 , (3-3)/2 ⇒ M(3,0)
- Now, As Given, N(a,b) is the Midpoint Of C(1,6) and M(3,0).
Thus. N(a,b) = (1+3)/2 , (6+0)/2 ⇒ N(2,3)
Answer:
A) 10.38hours
B) 617.95 is the concerntration of CO
Step-by-step explanation:
A) when x=600
T= 0.0002x^2 - 0.316x + 127.9
T= 0.0002(600)^2 -0.316(600) + 127.9
T= 10.38secs
B) to find the concerntration, use Almighty formular
X=-b+-sqrt(b^2-4ac)/2a
0.0002x^2-0.316x-127.9=9
0.0002x^2 - 0.316x + 118.9=0
X= 0.316 +- sqrt(0.316^2) -4(0.0002×118.9)/(2×0.0002)
X= 0.316+(0.68817/0.0004)=962.05 or
X=-0.316 -0.68817/0.0004 =617.95
Therefore X is within the domain of 617.95 is the concerntration
Answer:
28 pounds
Step-by-step explanation:
We have a total of 5 boxes, now we know that each box weighs 9 pounds, therefore:
Total weight = 5 * 9 = 45 pounds
Which means there are 45 pounds in total.
We are told that the limit is exceeded by 17 pounds. To find the limit weight, it is necessary to subtract the total weight and the excess:
45-17 = 28 pounds
Therefore, the maximum weight allowed per shipment is 28 pounds.
