Answer:
1. Equivalent
2. Not equivalent
Step-by-step explanation:
1. Equivalent because there's 4 x's that you add all together and that makes 4x
2. Not equivalent because 5x means there's 5 x's or x + x + x + x + x not only 1 x plus a number 5
Rather than carrying out IBP several times, let's establish a more general result. Let

One round of IBP, setting


gives


This is called a power-reduction formula. We could try solving for
explicitly, but no need.
is small enough to just expand
as much as we need to.





Finally,

so we end up with


and the antiderivative is

Step-by-step explanation:
number of the total cookies ÷ the nber her brother ate
6÷2=3
Answer:
C) The initial value is 32, and the rate of change is 1.
Step-by-step explanation:
This is the correct answer for edge