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SCORPION-xisa [38]
3 years ago
7

En un salon de clases cuando se colocan cuatro alumnos en cada banca, 3 de ellos quedan sin puesto y cuando se colocan de a 5 en

cada banca sobran 2 puestos. ¿Cual es el menor numero de alumnos y de bancas que hay en el salon?
Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
5 0

Answer: 5 benches and 23 students

Step-by-step explanation:

I will answer in English.

We have E students and B benches.

If we sit 4 students per bench, we have 3 students left.

then:

E = 4*B + 3

And if we sit 5 students per bench, there are two places with no students sited.

E = 5*B - 2

now we can replace the E in the second equation with the right part in the first equation:

4*B + 3 = 5*B - 2

3 + 2  = 5*B - 4*B

5 = B

So we have 5 benches, and:

E = 4*5 + 3 = 23 students.

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Suppose that the probability of a baseball player getting a hit in an at-bat is 0.3089. If the player has 25 at-bats during a we
klio [65]

Answer:

P(X>9) = 0.3593

Step-by-step explanation:

Previous concepts  

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".  

Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=25, p=0.3089)  

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

For this case we want this probability:

P(X >9)

And we can use the complement rule like this:

P(X>9) = 1-P(X \leq 8)= 1-[P(X=0) + P(X=1) +....+P(X=8)]And we can find the individual probabilities like this:

P(X=0) =(25C0)(0.3089)^0 (1-0.3089)^{25-0} =0.0000974  

P(X=1) =(25C1)(0.3089)^1 (1-0.3089)^{25-1} =0.0011  

P(X=2) =(25C2)(0.3089)^2 (1-0.3089)^{25-2}=0.00584  

P(X=3) =(25C3)(0.3089)^3 (1-0.3089)^{25-3}= 0.02  

P(X=4) =(25C4)(0.3089)^4 (1-0.3089)^{25-4}=0.049  

P(X=5) =(25C5)(0.3089)^5 (1-0.3089)^{25-5}=0.092  

P(X=6)=(25C6) (0.3089)^6 (1-0.3089)^{25-6} = 0.138

P(X=7) =(25C7)(0.3089)^7 (1-0.3089)^{25-7}=0.167

P(X=8) =(25C8)(0.3089)^8 (1-0.3089)^{25-8}=0.168

And in order to do the operations we can use the following excel code:

"=1-BINOM.DIST(8,25,0.3089,TRUE)"  

And we got:

P(X>9) = 0.3593

4 0
3 years ago
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