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SCORPION-xisa [38]
3 years ago
7

En un salon de clases cuando se colocan cuatro alumnos en cada banca, 3 de ellos quedan sin puesto y cuando se colocan de a 5 en

cada banca sobran 2 puestos. ¿Cual es el menor numero de alumnos y de bancas que hay en el salon?
Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
5 0

Answer: 5 benches and 23 students

Step-by-step explanation:

I will answer in English.

We have E students and B benches.

If we sit 4 students per bench, we have 3 students left.

then:

E = 4*B + 3

And if we sit 5 students per bench, there are two places with no students sited.

E = 5*B - 2

now we can replace the E in the second equation with the right part in the first equation:

4*B + 3 = 5*B - 2

3 + 2  = 5*B - 4*B

5 = B

So we have 5 benches, and:

E = 4*5 + 3 = 23 students.

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What is an equation of the line that passes through the points (-3, -2)(−3,−2) and (3, 6)(3,6)? Put your answer in fully reduced
il63 [147K]

Answer:

The equation of the line is y = \frac{4}{3} x + 2

Step-by-step explanation:

The form of the equation that passes through two points (x1, y1) and (x2, y2) is y = m x + b, where

  • m is the slope of the line whose rule is m=\frac{y2-y1}{x2-x1}
  • b is the y-intercept, you can find it by substituting x, y in the equation by (x1, y1) OR (x2, y2)

Let us solve the question:

∵ The line passes through the points (-3, -2) and (3, 6)

∴ x1 = -3 and x2 = 3

∴ y1 = -2 and y2 = 6

→ Use the rule of m to find it

∵ m=\frac{6-(-2)}{3-(-3)}=\frac{6+2}{3+3}=\frac{8}{6}

→ Simplify it by dividing up and down by 2

∴ m = \frac{4}{3}

→ Substitute its value in the form of the equation above

∴ y = \frac{4}{3} x + b

→ To find b substitute x and y by x1 and y1

∴ -2 = \frac{4}{3} (-3) + b

∴ -2 = -4 + b

→ Add 4 to both sides

∴ -2 + 4 = -4 + 4 + b

∴ 2 = b

→ Substitute it in the form of the equation

∴ y = \frac{4}{3} x + 2

∴ The equation of the line is y = \frac{4}{3} x + 2

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Product of two natural numbers p and q is 590 and their hcf is 59. how many set of values of p and q is possible
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\text{Let the product of two natural numbers p and q is 590, and their HCF is 59}\\
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\text{we know that the product of LCM and HCF of any two numbers is equal}\\
\text{to the product of the numbers. that is}\\
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\text{but here we can see that }LCM

Hence there is no such natural numbers exist.

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