The three scores are 86, 74, and an unknown score x. The average (i.e. the sum divided by how many there are) is 80, so we have
Multiply both sides by 3 and you get
Subtract 160 from both sides to get
Note: you could solve this exercise very quickly if you notice that the two numbers, 86 and 74, are symmetrical with respect to 80, which is the average. So, the third number must be the average.
Let's see which of these best measures the data.
The mean is the average, or the sum of all numbers divided by the total numbers there are.
4.8 + 3 + 2.7 + 4.4 + 4.8 + 9.9 = 29.6
There are 6 numbers total.
29.6/6 = 4.93.
The mean is 4.93.
Let's try our median. The median is the middle number of a sequence listed from least to greatest. I will make the list for you.
2.7, 3, 4.4, 4.8, 4.8, 9.9.
Cross out the smallest number with the greatest number.
3, 4.4, 4.8, 4.8.
4.4, 4.8.
Since we do not have a middle number, we must see what number is in the middle of 4.4, and 4.8. To determine this, we must average. Add 4.4 and 4.8, then divide by 2.
9.2/2 = 4.6.
4.6 is our median.
The mode is the number that appears the most, so let's find the number that is the most frequent.
4.8 is our mode.
The best number that will fit in this to make it work out is 4.6.
The median is your answer, B.)
I hope this helps!
Answer:
Let n be the number of 25 cent stamps.Then, 28 - n must be the number of 29 cent stamps.Tim paid $7.60 the stamps.
0.25n + 0.29(28 - n) = 7.60
This means that n stamps at 25 cents a piece plus (28 - n) stamps at 29 cents a piece sum to $7.60.Solve for m.
0.25n + 8.12 - 0.29n = 7.60
-0.04n = -0.52
n = 13
So, Tim bought 13 25-cent stamps and 28 - 13 = 15 29-cent stamps
Step-by-step explanation:
hope this helps:)
The dimensions are 15x35 meters
If the line is perpendicular, then its slope is the reciprocal of the given line's slope. This new line's slope is 1/2. We plug it into slope-intercept form
y = 1/2x + b
Now plug in the given point of (2, 10) and solve for b.
10 = 1/2(2) + b
10 = 1 + b
9 = b
So your equation is y = 1/2x + 9
