Question

5x+7y=40,3x-7y=0 in linear equations​

Answer 1

Answer:

(5, $\frac{15}{7}$ )

Step-by-step explanation:

Given the 2 equations

5x + 7y = 40 → (1)

3x - 7y = 0 → (2)

Adding the 2 equations term by term will eliminate the y- term

8x + 0 = 40

8x = 40 ( divide both sides by 8 )

x = 5

Substitute x = 5 into either of the 2 equations and solve for y

Substituting into (1)

5(5) + 7y = 40

25 + 7y = 40 ( subtract 25 from both sides )

7y = 15 ( divide both sides by 7 )

y = $\frac{15}{7}$

solution is (5, $\frac{15}{7}$ )