x/3+17is less than or equal to 15
x/3is less than or equal to 15-17
xis less than or equal to -6
P = 3
n = 5
N = 15
<span><span><span>x </span><span>¯ </span></span> </span>
= 16
<span><span>SST</span> </span>
= <span><span>∑n(x−<span><span>x </span><span>¯ </span></span><span><span>) </span><span>2 </span></span></span> </span>
<span><span>SST</span> </span>
= <span><span>5(12−16<span><span>) </span><span>2 </span></span>+5(16−16<span><span>) </span><span>2 </span></span>+11(20−16<span><span>) </span><span>2 </span></span></span> </span>
= 160
<span><span>MST</span> </span>
= <span><span><span><span>SST</span><span>p−1</span> </span> </span>
</span>
<span><span>MST</span> </span>
= <span><span><span>160<span>3−1</span> </span> </span>
</span>
= 80
<span><span>SSE</span> </span>
= <span><span>∑(n−1)<span><span>S </span><span>2 </span></span></span> </span>
SSE = 4*4 + 4*1 + 4*16
= 84
<span><span>MSE</span> </span>
= <span><span><span><span>SSE</span><span>N−p</span> </span> </span>
</span>
<span><span>MSE</span> </span>
= <span><span><span>84<span>15−3</span> </span> </span>
</span>
MSE = 7
<span>F </span>
= <span><span><span><span>MST</span><span>MSE</span> </span> </span>
</span>
<span>F </span>
= <span><span><span>807 </span> </span>
</span>
= 11.429
A asymptote
b growth/decay
c initial amount
Answer:
just add 2.5 to Lin's distance and 3 to Andre's distance. eventually you will reach a point where their values are the same. Then the hour next to it is the answer you are looking for
Step-by-step explanation:
<span>2500(1 + .03/6)^12 = 2654.19
Your answer is $2654.2
Hope this helps!</span>
