1) I put them in two separate brakets.
2) I solved it by equating both of them.
Answer:
33
Step-by-step explanation:
the answer is in the above image
If you assign variables to the problem, it can make things a lot simpler. Lets say chairs are x and tables are y. Therefore you have:
2x+6y=40
5x+3y=25
Now you can isolate the variable of one equation and put it into another (it doesn't matter which. I'm going to manipulate the top equation to plug into the bottom one).
2x=40-6y
x=20-3y
Now I plug into bottom equatioin:
5(20-3y) + 3y=25
100-15y+3y=25
100-12y=25
-12y=-75
y=$6.25
Now you can plug in y in either equation to get x.
2x+6(6.25)=40
37.5+2x=40
2x=2.5
x=1.25
So it costs $6.25 for each table and $1.25 for each chair. If you think about it, it would make sense for the table to cost more for the chair.
Answer:
6
Step-by-step explanation:
We have two fractions and are asked to find the answer if they both are divided.
3/5 and 1/10.
When we divide fractions, we need to follow KCF
KEEP - Keep the fractions
CHANGE - Change the division sign to a multiplication sign
FLIP - Flip the second fraction
Follow :
KEEP :
3/5 / 1/10
CHANGE :
3/5 * 1/10
FLIP :
3/5 * 10/1
Now we need to multiply, which is simple because it's multiplying across :

30/5
Simplify by dividing the numerator and denominator by 5 :

Divide the numerator by denominator :

A and D are correct. To understand this, you need to know that this scenario gives us a total (2 1/2 cups) and a part (1/4). When you have these 2 pieces of information you have either a division problem with a total divided into parts (choice D) or you have one part and a totol shown as a multiplication problem (choice A).