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Inessa05 [86]
2 years ago
15

Factor out the greatest common factor. If the greatest common factor is 1, just retype the polynomial.

Mathematics
1 answer:
Sholpan [36]2 years ago
6 0

Answer:

3u(u - 2)

Step-by-step explanation:

greatest common factor: 3u (both are divisible by 3, and include the variable u)

factor: 3u^2/3u = u; -6u/3u = 2

new polynomial: 3u(u - 2)

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A researcher is interested in knowing the average height of the men in a village. To the researcher, the population of interest
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Answer:

The population mean height of men in the village is 5.78 feet.

The sample mean height of men in the village is 7.8 feet.

Step-by-step explanation:

It is provided that the researcher's interest is in knowing the average height of the men in a village.

To the researcher, the population of interest is the <em><u>men</u></em><em> </em>in the village, the relevant population data are the <em><u>height of men</u></em> in the village, and the population parameter of interest is the <em><u>mean height of men</u></em>.

It is also provided that there are 590 men in the village, and the sum of their heights is 3,410.2 feet.

Compute the average height as follows:

\bar X_{H}=\frac{3410.2}{590}=5.78\ \text{feet}

Thus, the population mean height of men in the village is 5.78 feet.

It is given that the researcher measured the heights of 18 village men and calculated the average to estimate the average height of all the village men.

The sample for his estimation is <em><u>18 men</u></em>, the relevant sample data are the <em><u>heights of the 18 men</u></em>, and the sample statistic is the <em><u>sample mean height</u></em>.

It is also given that the  sum of the heights of the 18 village men is 104.4 feet.

Compute the average height of the 18 men as follows:

\bar x_{H}=\frac{104.4}{18}=7.8\ \text{feet}

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We gave a national verbal proficiency test that has a mean score of 500 with a standard deviation of 75. What raw score would co
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Answer:

519

Step-by-step explanation:

Let's assume that the scores for the national verbal proficiency test follow a normal distribution.

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The raw score to the 60th percentile is 519.

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