The hyperbolic cos (cosh) is given by
cosh (x) = (e^x + e^-x) / 2
The slope of a tangent line to a function at a point is given by the derivative of that function at that point.
d/dx [cosh(x)] = d/dx[(e^x + e^-x) / 2] = (e^x - e^-x) / 2 = sinh(x)
Given that the slope is 2, thus
sinh(x) = 2
x = sinh^-1 (2) = 1.444
Therefore, the curve of y = cosh(x) has a slope of 2 at point x = 1.44
Answer:
y = -2/3x - 3
Step-by-step explanation:
First, write the equation using the slope. It should look like this: y = -2/3x + b. Next, find the y intercept by plugging in the point. This is what it looks like: -1 = -2/3(-3) + b. Multiply -2/3 by -3 to get 2. This is what it should look like now: -1 = 2 + b. Subtract 3 from both sides to get -3 = b. Go back to your original equation and plug in -3 for b. This is your final equation:
y = -2/3x - 3
Hope this helped! :)
Answer:
f(y) = 12 + 4x
Step-by-step explanation:
Output is 12 more than 4 timea the input
The dependent variable = y
The dependent variable = x
The input is the independent variable, x
Output is the dependent variable, y
Output = 12 + (4 * input)
Hence, the function rule can be written has :
f(y) = 12 + 4x
She worked 2 1/2 hrs yesterday and 4 1/4 hrs today...
2 1/2 + 4 1/4 =
2 + 4 = 6
1/2 + 1/4 = 2/4 + 1/4 = 3/4
so she worked a total of 6 3/4 hrs....or 6.75 hrs
she is paid $ 54
54 / 6.75 = $ 8 per hr <=== what she earned per hr
Answer:
D.300 sq ft , 15 X 20 = 300
