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xenn [34]
3 years ago
10

(11x^2+5y^2-8xy)+(x^2-7y^2+4x)

Mathematics
1 answer:
CaHeK987 [17]3 years ago
7 0

Answer:

4x2 - 3xy - 9y2

Step-by-step explanation:

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A set of wrist watch prices are normally distributed with a mean of 767676 dollars and a standard deviation of 101010 dollars. W
Akimi4 [234]

Answer:

0.8224

Step-by-step explanation:

Data

  • mean: $76
  • standard deviation, sd: $10
  • first value of interest, x1: $63
  • second value of interest, x2: $90

z-score for x1:

z1 = (x1 - mean)/sd = (63 - 76)/10 = -1.3

z-score for x2:

z2 = (x2 - mean)/sd = (90 - 76)/10 =  1.4

The  proportion of wrist watch prices are between $63 and $90 is:

P(z1 < z < z2) = P(z < 1.4) - P(z < -1.3)

P(z < 1.4) = 0.9192 (see first picture attached)

P(z < -1.3) = 0.0968 (see second picture attached)

P(z1 < z < z2) = 0.9192 - 0.0968 = 0.8224

7 0
3 years ago
What do you think the answer is?
spin [16.1K]
C. $17.28
1.92•9=17.28
4 0
3 years ago
Read 2 more answers
How old are all you?
Wewaii [24]

Answer: I do not age

Step-by-step explanation: I have magical Phoenix powers and i drink a lot of ageless potions

8 0
3 years ago
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Which equation could be used to solve y 2+7y=18 by factoring?
oee [108]
 <span>(y + 9)(y - 2) = 0  would be the correct answer .</span>
5 0
3 years ago
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Tutorial Exercise A boat leaves a dock at 2:00 PM and travels due south at a speed of 20 km/h. Another boat has been heading due
ANTONII [103]

Answer:

Both the boats will closet together at 2:21:36 pm.

Step-by-step explanation:

Given that - At 2 pm boat 1 leaves dock and heads south and boat 2 heads east towards the dock. Assume the dock is at origin (0,0).

Speed of boat 1 is 20 km/h so the position of boat 1 at any time (0,-20t),

        Formula :   d=v*t

at 2 pm boat 2 was 15 km due west of the dock because it took the boat 1 hour to reach there at 15 km/h, so the position of boat 2 at that time was (-15,0)

the position of boat 2 is changing towards east, so the position of boat 2 at any time (-15+15t,0)

      Formula : D=\sqrt{(x2-x1)^2+(y2-y1)^2}

⇒                     D = \sqrt{20^2t^2+15(t-1)^2}

Now let           F(t) = D^2(t)

                ∵    F'(t) = 800t + 450(t-1) =  1250t -450\\F'(t) =0

⇒                     t= 450/1250

⇒                     t= .36 hours

⇒                       = 21 min 36 sec

Since F"(t)=0,

∴ This time gives us a minimum.

Thus, The two boats will closet together at 2:21:36 pm.

3 0
3 years ago
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