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2 years ago

10

(11x^2+5y^2-8xy)+(x^2-7y^2+4x)

1 answer:

CaHeK987 [17]2 years ago

7 0

Answer:

4x2 - 3xy - 9y2

Step-by-step explanation:

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A breeder reactor converts uranium-238 into an isotope of plutonium-239 at a rate proportional to the amount of uranium-238 pres

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Let $U(t)$ denote the amount of uranium-238 in the reactor at time $t$ . As conversion to plutonium-239 occurs, the amount of uranium will decrease, so the conversion rate is negative. Because the rate is proportional to the current amount of uranium, we have

$\dfrac{\mathrm dU}{\mathrm dt}=-kU$

where $k>0$ is constant. Separating variables and integrating both sides gives

$\dfrac{\mathrm dU}U=-k\,\mathrm dt\implies\ln|U|=-kt+C\implies U=Ce^{-kt}$

Suppose we start some amount $u$ . This means that at time $t=0$ we have $U(0)=u$ , so that

$u=Ce^{-0k}\implies C=u\implies U=ue^{-kt}$

We're given that after 10 years, 99.97% of the original amount of uranium remains. This means (if $t$ is taken to be in years) for some starting amount $u$ ,

$0.9997u=ue^{-10k}\implies k=-\dfrac{\ln(0.9997)}{10}$

The half-life is the time $t_{1/2}$ it takes for the starting amount $u$ to decay to half, $0.5u$ :

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3 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

How do I solve 1/10x+5=-3x-13+4x ?

Temka [501]

Answer:

x = 20

I am not sure if you wanted the answer. Sorry!

Step-by-step explanation:

Let's solve your equation step-by-step.

1/10 x + 5 = - 3x - 13 + 4x

Step 1: Simplify both sides of the equation.

1/10 x + 5 = - 3x - 13 + 4x

1/10 x + 5 = - 3x + - 13 + 4x

1/10 x + 5 = (<em>- 3x + 4x</em>) + (- 13)

1/10 x + 5 = <em>x</em> + - 13

1/10 x + 5 = x - 13

Step 2: Subtract x from both sides.

1/10 x + 5 - <em>x </em>= x - 13 - <em>x</em>

- 9/10 x + 5 = - 13

Step 3: Subtract 5 from both sides

- 9/10 x + 5 - <em>5</em> = - 13 - <em>5</em>

- 9/10 x = - 18

Step 4: Multiply both sides by 10/(- 9).

(<em>10/ - 9</em>) * (- 9/10 x) = (<em>01/ - 9</em>) * (- 18)

x = 20

Hope this helps!

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