3 years ago

1 point

1 answer:

8 0

I think the answer is D but i could be wrong

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marshall27 [118]

Yeah i did this test on ingenuity and the answer is 15. your welcome

5 0

3 years ago

Degger [83]

$\displaystyle\lim_{x\to0^+}x\ln x^3=\lim_{x\to\infty}\frac{\ln\frac1{x^3}}x=-3\lim_{x\to\infty}\frac{\ln x}x=\frac\infty\infty$

L'Hopital's rule tells us the limit is equal to

$-3\displaystyle\lim_{x\to\infty}\frac{\frac1x}1=0$

6 0

4 years ago

aleksklad [387]

Equation is y = 6x - 4

Step-by-step explanation:

Step 1: Find the slope of the line using m = (y2 - y1)/(x2 - x1) Here x1 = 0, x2 = 1, y1 = -4, y2 = 2

⇒ m = (2 - -4)/(1 - 0) = 6

⇒ y = 6x - 4

4 0

3 years ago

Mandarinka [93]

Answer:

81.7 in (nearest tenth)

Step-by-step explanation:

$\textsf{Circumference of a circle}=\sf 2 \pi r\quad\textsf{(where r is the radius)}$

Given:

Substituting given value into the formula:

$\begin{aligned}\implies \textsf{Circumference} & =2 \pi \cdot 13\\ & = 26 \pi\\ & = 81.7\: \sf in\:(nearest\:tenth)\end{aligned}$

5 0

2 years ago

Marat540 [252]

Y - y1 = m(x - x1)
slope(m) = -1/7
(3,3)...x1 = 3 and y1 = 3
now we sub
y - 3 = -1/7(x - 3) <==

4 0

4 years ago