The coordinates of a particle of water "t" seconds after it leaves the end of the fire hose will be
.. (x, y) = (38.4*cos(47.5°)t, -4.9t^2 +38.4*sin(47.5°)t)
Solving for t, we have
.. t = x/(38.4*cos(47.5°)
For x = 25.7 meters, t is about 0.99065 seconds.
Then y will be
.. -4.9*(0.99065)^2 +38.4*sin(47.5°)*0.99065 = 23.238 . . . . meters
The water will hit the building about 23.24 meters above the height of the hose.
Answer:
It is in quadrant three
Step-by-step explanation:
The points of M means there x and y will both be negatives.
Answer:
B is the right answer.
Step-by-step explanation:
56 + 0.08x = 164
0.08x = 164 - 56
0.08x = 108
0.08x/0.08 = 108/0.08
x = 1,350
To confirm that:
56 + 0.08x
56 + 0.08(1,350)
56 + 108
= 164
164 is the answer.
Answer:
D) cot(C) = 1/2.
Step-by-step explanation:
We can go through each choice and examine is validity.
Choice A)
We have:

Recall that secant is the ratio of the hypotenuse to the adjacent.
With respect to B, the adjacent is 6 and the hypotenuse is 7.
Therefore, sec(B) should be 7/6 instead.
A is incorrect.
Choice B)
We have:

Cotangent is the ratio of the adjacent side to the opposite.
With respect to B, the adjacent side is 6 and the opposite side is 3.
Therefore, cot(B) = 6/3 = 2.
B is incorrect.
Choice C)
C is incorrect for the reasons listed in A.
Choice D)
We have:

Again, cotangent is the ratio of the adjacent side to the opposite.
With respect to C, the adjacent side is 3 and the opposite side is 6.
So, cot(C) = 3/6 = 1/2.
Therefore, D is the correct choice!
Answer: A, -2 and 4
Step-by-step explanation: cause it it you’re welcome