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maria [59]
3 years ago
14

How to rewrite equation 5x+7y-35=0 in slope intercept form?​

Mathematics
1 answer:
tino4ka555 [31]3 years ago
3 0
Y equals 5 over 7x minus 5
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The function below shows the number of car owners f(t), in thousands, in a city in different years t:
stepladder [879]

Answer:

6.3


Step-by-step explanation:


  • <u>The number of car owners f(t) </u><u>in year 5</u><u> is found by plugging in 5 into t of the equation:</u>

f(5)=1.1(5)^{2}-2.5(5)+1.5=16.5


  • <u>The number of car owners f(t) </u><u>in year 3</u><u> is found by plugging in 3 into t of the equation:</u>

f(3)=1.1(3)^{2}-2.5(3)+1.5=3.9


So there is a change of  16.5-3.9=12.6 in the 2 years. So to get per year, we divide 12.6 by 2, to get:

\frac{12.6}{2}=6.3


Hence, <em>"The average rate of change of f(t) from t = 3 to t = 5 is </em><em>6.3 </em><em>thousand owners per year."</em>

5 0
3 years ago
Read 2 more answers
Match the reason with the statements in the proof if the last line of the proof would be 6.&lt;3 and &lt;5 are supplementary bec
shusha [124]

nope i dont understand this either

3 0
3 years ago
Can somebody help me please
NeX [460]
For the first question, you need to count all of your choices. Kepp in mind, it will be a fraction. Then count all of your "V6". 

12/24 = 1/2
Hope this helps!!


4 0
3 years ago
Read 2 more answers
6. What is the density of water?
Naily [24]

Answer:

997 kg/m³

Step-by-step explanation:

I just looked it up, hopefully it's the right answer

6 0
3 years ago
The weights of the chocolate in Hershey Kisses are normally distributed with a mean of 4.5338 g and a standard deviation of 0.10
dusya [7]

The distribution is not a standard normal distribution.

We know that the variable (X) usually obeys and follows a standard normal distribution provided that the summation of (X) is zero and the variance of the random variable V(X) = 1.

Mathematically:

E(X) = 0 and V(X) = 1

Given that;

  • the mean which follows a normal distribution (X) = 4.5338 g, and
  • the standard deviation SD(X) = 0.1039 g

As such, the distribution is not a standard normal distribution.

Therefore, we can conclude that the distribution is not a standard normal distribution.

Learn more about standard normal distribution here:

brainly.com/question/11876263?referrer=searchResults

7 0
3 years ago
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