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Mazyrski [523]
3 years ago
13

Heidi is making a tower using sugar cubes. Each sugar cube has a side length of 1 cm. Each layer has 4 sugar cubes, arranged in

a 2 by 2 pattern. The completed tower has a volume of 24 cm3. How many layers of sugar cubes are in the tower?
Mathematics
1 answer:
Archy [21]3 years ago
4 0

Answer:

3 layers

Step-by-step explanation:

Given

L = 1cm --- side length of the cube

Each layer = 2 * 2 cube

Volume = 24cm^3

Required

Determine the number of layers

First, we calculate the volume of each layer:

The length of the layer is:

Length = 2 * L

Length = 2 * 1cm

Length = 2cm

Next, we calculate the volume of each layer:

Volume = Length^3

Volume = (2cm)^3

Volume = 8cm^3

The number of layer is calculated by dividing the volume of the tower by the volume of each layer

Layers = \frac{24cm^3}{8cm^3}

Layers = 3

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If 5 tickets cost $11.00, how much do 20 tickets cost?
user100 [1]

Answer: 44 dollars

Step-by-step explanation:

so there is two ways to do this so ill show you both and you can see which one is easier for you!

method 1- divide the total amount of tickets by the amount with the cost. Then multiply that number by the cost

20/5=4     4*11=44

method 2- divide the money by the number with the cost. Then multiply it by the total amount of tickets.

11/5=2.2     2.2*20=44

7 0
3 years ago
BRAINLIEST ANSWER WINS! A satellite is to be put into an elliptical orbit around a moon as shown below. A vertical ellipse is sh
bekas [8.4K]

Answer:

D. x²/1953²  + y²/ 1466² = 1

Step-by-step explanation:

==>Given:

Radius of spherical moon = 1000km

Distance of satellite from moon surface = 953km to 466km

==>Required:

Derived equation of ellipse

==>Solution:

The formula for driving an equation of ellipse is given as:

x²/a² + y²/b² = 1

Where,

a = length of the semi-major axis, while,

b = length of the semi-major axis

Since we are told that the satellite distance to the surface of the moon varies from 953km to 466km, values of a and b is calculated by summing each length to the radius of the moon as follows:

a = radius of moon + the larger distance of the satellite = 1000+953 = 1,953km

b = radius of moon + the smaller distance of the satellite = 1000+466 = 1,466km

Thus, the equation of the ellipse would be:

x²/1953²  + y²/ 1466² = 1

8 0
3 years ago
Dataset: 147; 159; 164; 182; 172; 171; 162; 163; 157; 145; 164; 188; 172; 163; 162; 164 and 166. a) Arrange the data into a stem
Molodets [167]

The mean of data is 164.70, median and mode of data are 164

Given that Dataset: 147; 159; 164; 182; 172; 171; 162; 163; 157; 145; 164; 188; 172; 163; 162; 164 and 166. and asked to arrange data in stem and leaf diagram and asked to determine mean, mode and median form the stem and leaf diagram

STEM                                    LEAF

14                                           5         7
15                                                       7    9
16                    2 2 3 3 4 4 4         6
17                  1 2 2
18                      2                                  8

Mean =\frac{total sum}{numberof terms}

Mean=\frac{2800}{17}

Mean= 164.70

Median⇒since there are 17 terms

Median= \frac{N+1}{2}the term

Median=9th term=164

Mode⇒ most frequent number

Mode⇒164

Therefore, 164 is mode and median ,164.70 is mean

Hence,The mean of data is 164.70, median and mode of data are 164

Learn more about mean here:

brainly.com/question/13451489

#SPJ9

3 0
2 years ago
I need some help with this, it doesn't make much sense to me.
alukav5142 [94]

Answer: Hi. Im a 6th grader what exactly are you struggling with?

Step-by-step explanation:

3 0
3 years ago
PLEASE HELP! Solve each of the following by using the general quadratic formula.
Archy [21]

Using the quadratic formula, the solutions are:

a) x = \frac{3 \pm \sqrt{41}}{4}

b) x = 1 \pm 2i

<h3>What is a quadratic function?</h3>

A quadratic function is given according to the following rule:

y = ax^2 + bx + c

The solutions are:

x_1 = \frac{-b + \sqrt{\Delta}}{2a}

x_2 = \frac{-b - \sqrt{\Delta}}{2a}

In which:

\Delta = b^2 - 4ac

Item a:

The coefficients are a = 2, b = -3, c = -4, hence:

  • \Delta = (-3)^2 - 4(2)(-4) = 41
  • x_1 = \frac{3 + \sqrt{41}}{4}
  • x_2 = \frac{3 - \sqrt{41}}{4}

Item b:

The coefficients are a = 1, b = 2, c = 2, hence:

  • \Delta = (2)^2 - 4(1)(2) = -4
  • x_1 = \frac{2 + \sqrt{-4}}{2} = 1 + 2i
  • x_2 = \frac{2 - \sqrt{-4}}{2} = 1 - 2i

More can be learned about quadratic equations at brainly.com/question/24737967

#SPJ1

6 0
2 years ago
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