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Volgvan
2 years ago
5

Hi I'm looking to solve this question for my work but I'm super stuck and I need help asap. Thsnks

Mathematics
1 answer:
MrMuchimi2 years ago
8 0
10w + 9 Are you combing like terms?
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What is the 8th term of 6,2,2/3
devlian [24]

Answer:

2/729

Step-by-step explanation:

I think that is the answer I hope it helps

3 0
2 years ago
What is the domain and range of y+3=2^x
Bad White [126]

Answer: y>-3 and x is all real numbers


5 0
2 years ago
PLEASE HELP ASAP!!!!!!
sammy [17]

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g(x)=f(x+3)+5

Step-by-step explanation:

8 0
3 years ago
Angle C is 60 degrees and angle CAB is 78 we need to find angle DAB
ioda

Answer:

∠ DAB = 48°

Step-by-step explanation:

The sum of the 3 angles in Δ ACD = 180° , then

∠ CAD + 60° + 90° = 180° , that is

∠ CAD + 150° = 180° ( subtract 150° from both sides )

∠ CAD = 30°

Then

∠ DAB + ∠ CAD = ∠ CAB

∠ DAB + 30° = 78° ( subtract 30° from both sides )

∠ DAB = 48°

5 0
2 years ago
Question:
faltersainse [42]

Answer:

The probability that a ship that is declared defecive is sound is 0.375

Step-by-step explanation:

Let P(A|B) denote the conditional probability of A given B. We will make use of the equation

P(A|B) = P(A) × P(B|A) / P(B)

We have the probabilities:

  • P(Declared Defective (detected) | Defective) = 0.95
  • P(not Detected | Defective) = 1-0.95=0.05
  • P(Declared Sound | Sound) = 0.97
  • P(Declared Defective |Sound) = 1-0.97=0.03
  • P(Defective)=0.05
  • P(Sound)= 1- 0.05 = 0.95

We can calculate:

P(Declared Defective)= P(Detected | Defective)×P(Defective) + P(Declared Defective |Sound) ×P(Sound) = 0.95×0.05 + 0.03×0.95=0.076

P(S | Declared Defective) =

(P(Sound) × P(Declared Defective | Sound)) / P(Declared Defective)

=0.95×0.03 /0.076 =0.375

3 0
2 years ago
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