Hi I'm looking to solve this question for my work but I'm super stuck and I need help asap. Thsnks

I'm thinking of a ten-digit integer whose digits are all distinct. It happens that the number formed by the first n of them is d

PIT_PIT [208]

The problem here takes a brilliant mind to answer this. This problem can easily be answered using programming because we can not then and there push all the possibilities using paper and pen.
The answer is 3816547290.
Trying all the possibilities starting form 1000000080 (we are sure that the last number should be 0). Then traversing that number until 9999999990. Each traverse, check the number if its divisible to n, so on and so forth.

3 0

2 years ago

Match the expression with its name. 7x4 – 5x + 4

Anettt [7]

Answer:

algebraic expression

28-20=8

4 0

2 years ago

Which point is located in Quadrant I?,

KiRa [710]

Answer:

the point with coordinates (-3,4)is located in quadrantll

5 0

2 years ago

Can someone give me a question that's dividing fractions and then I'll message you and you give me the answer

ra1l [238]

What is the answer to this fraction division problem? 1/8÷1/16

5 0

3 years ago

indicate the equation of the line that is the perpendicular bisector of the segment with endpoints (4,1) and (2,-5)

bulgar [2K]

hmmm what would it be the bisector point of a line with those points? let's check

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{4}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{-5}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{2+4}{2}~,~\cfrac{-5+1}{2} \right)\implies \implies \left( \cfrac{6}{2}~,~\cfrac{-4}{2} \right)\implies (3,-2)$

now, let's check the slope of those two points, bearing in mind that a perpendicular line will have a <u>negative reciprocal slope</u> to that one.

$\bf (\stackrel{x_1}{4}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{-5}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-5-1}{2-4}\implies \cfrac{-6}{-2}\implies 3 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{3\implies \cfrac{3}{1}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{1}{3}}\qquad \stackrel{negative~reciprocal}{-\cfrac{1}{3}}}$

so, we're really looking for the equation of a line whose slope is -1/3 and runs through (3, -2)

$\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{-2})~\hspace{10em} slope = m\implies -\cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-2)=-\cfrac{1}{3}(x-3)\implies y+2=-\cfrac{1}{3}x+1 \\\\\\ y=-\cfrac{1}{3}x+1-2\implies y=-\cfrac{1}{3}x-1$

7 0

2 years ago