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Leona [35]
4 years ago
9

A monument casts a 40 ft shadow. Adam is 6 ft tall and casts a 5 foot shadow. How tall is the monument

Mathematics
1 answer:
OLga [1]4 years ago
3 0
The answer is 48 feet (D).

Explanation:

To solve this, you must think of the monument and its shadow and Adam and his shadow as a triangle, the person/object being the vertical leg, the shadows being the horizontal leg, and a line connecting them being the hypotenuse.  Also, we can assume that these triangles are similar.  First, we can set the scale to be 40/5 (the two shadows set a scale because the triangles are similar).  Then, we can put x/6 (the actual things are similar, and the scale was established to be building/measurement).  Next, we can set the two fractions equal to each other (40/5 = x/6) and solve.  We can cross multiply to get 5x = 40 * 6.  That goes to  5x = 240.  Finally, we can divide by five on each side to get x = 48 feet (D).
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Answer:

1728

280

Step-by-step explanation:

16x12x9=1728

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8 0
3 years ago
In the past year and a half, Gnarly the dog lost an average of 2/9 pound each month. Today, Gnarly weighs 14 pounds. How much di
svlad2 [7]

Answer:

Weight before 18 month = 18 pound

Step-by-step explanation:

Given:

Current weight of dog = 14 pound

Weight lose each month = 2/9 pound

Total number of month = 1\frac{1}{2} year = 18 month

Find:

Weight before 18 month

Computation:

Total weight lose = Weight lose each month x Total number of month

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3 years ago
3. Derek throws a baseball upward from an initial height of 3 ft. The baseball hits the ground after 2 seconds.
mariarad [96]

Answer with Step-by-step explanation:

Since we have given that

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The baseball hits the ground after 2 seconds

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So, final velocity = v = 0

a. What was the initial velocity of the baseball?

Initial velocity is given by

v_0=\dfrac{3}{2}=1.5\ ft/sec

b. What is the function that models the height, ℎ (in feet), of the baseball over a period of time tt (in seconds)?

As we know that the function of height would be

h(t)=-16t^2+v_0t+h_0

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So, our function becomes,

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c. At what time did the baseball reach its maximum height? What was the maximum height of the baseball?

Maximum height at time t:

t=\dfrac{-b}{2a}=\dfrac{-1.5}{2\times -16}=\dfrac{1.5}{32}\approx 0.05\ seconds

Maximum height would be

h(0.05)=-16(0.05)^2+1.5\times 0.05+3=3.035\ ft

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yes please check my most recent question

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