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2 years ago

A motorcycle raced around a track at a speed of 110 miles per hour.

1 answer:

4 0

If it’s going 110mph, and the question if asking how many mph will it go for half an hour. Simply just take 110 divided by 2.
Which gives u 55

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Can someone solve this

valentinak56 [21]

triangle TUV is congruent to triangle TBA

by SAS congruency

hope it helps...!!!!

3 0

1 year ago

B = 3m + 2p<br> Work out the value of p when B= 2 and m = 5

GarryVolchara [31]

This is called a "substitution problem" is where you have variable that have defined values and plug them in value calculate the expression.

B = 3m + 2p # Starting equation

2 = (3)(5) + 2p # Substitution

2 = 15 + 2p # Multiplication

-13 = 2p # Subtract 15 from both sides

$\frac{-13}{2}$ = p # Divide both sides from 2

p = $\frac{-13}{2}$ # Use the reflexive property of equality

Hope this helps!

6 0

2 years ago

Read 2 more answers

Someone please be awesome and help me please :(

solong [7]

Answer:

$(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0$

$(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}$

$x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}$

Step-by-step explanation:

$x^2+\frac{b}{a}x+\frac{c}{a}=0$

They wanted to complete the square so they took the thing in front of x and divided by 2 then squared. Whatever you add in, you must take out.

$x^2+\frac{b}{a}x+(\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0$

Now we are read to write that one part (the first three terms together) as a square:

$(x+\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0$

I don't see this but what happens if we find a common denominator for those 2 terms after the square. (b/2a)^2=b^2/4a^2 so we need to multiply that one fraction by 4a/4a.

$(x+\frac{b}{2a})^2+\frac{4ac}{4a^2}-\frac{b^2}{4a^2}=0$

They put it in ( )

$(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0$

I'm going to go ahead and combine those fractions now:

$(x+\frac{b}{2a})^2+(\frac{-b^2+4ac}{4a^2})=0$

I'm going to factor out a -1 in the second term ( the one in the second ( ) ):

$(x+\frac{b}{2a})^2-(\frac{b^2-4ac}{4a^2})=0$

Now I'm going to add (b^2-4ac)/(4a^2) on both sides:

$(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}$

I'm going to square root both sides to rid of the square on the x+b/(2a) part:

$x+\frac{b}{2a}=\pm \sqrt{\frac{b^2-4ac}{4a^2}}$

$x+\frac{b}{2a}=\pm \frac{\sqrt{b^2-4ac}}{2a}$

Now subtract b/(2a) on both sides:

$x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}$

Combine the fractions (they have the same denominator):

$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

6 0

2 years ago

Howard is designing a chair swing ride. The swing ropes are 4 44 meters long, and in full swing they tilt in an angle of 2 3 ∘ 2

qaws [65]

Question:

Howard is designing a chair swing ride. The swing ropes are 4 meters long, and in full swing they tilt in an angle of 23°. Howard wants the chairs to be 3.5 meters above the ground in full swing. How tall should the pole of the swing ride be? Round your final answer to the nearest hundredth.

Answer:

7.18 meters

Step-by-step explanation:

Given:

Length of rope, L = 4 m

Angle = 23°

Height of chair, H= 3.5 m

In this question, we are to asked to find the height of the pole of the swing ride.

Let X represent the height of the pole of the swing ride.

Let's first find the length of pole from the top of the swing ride. Thus, we have:

$cos \theta = \frac{h}{L}$

Substituting figures, we have:

$cos(23) = \frac{h}{4}$

Let's make h subject of the formula.

$h = 4cos(23) = 3.68$

The length of pole from the top of the swing ride is 3.68 meters

To find the height of the pole of the swing ride, we have:

X = h + H

X = 3.68 + 3.5

X = 7.18

Height of the pole of the swing ride is 7.18 meters

3 0

2 years ago

Liam invests £8000 in a savings account for 4 years. The savings account pays compound interest at a rate of: 4.5 % for the firs

madam [21]

Answer:

The value of Liam's investment at the end of 4 years is £9069.764

Step-by-step explanation:

Compound interest is interest calculated on the initial principal, which also includes all of the accumulated interest of previous periods of an investment.

We multiply the principal amount by one plus the annual interest rate to the power of the number of compound periods to get a combined figure for principal and compound interest.

4.5% in the first year;

4.5/100 = 0.045

(1 + 0.045) × 8000 =

1.045 × 8000 = £8360.

2.75% for all subsequent year;

2.75/100 = 0.0275

1 + 0.0275=1.0275

Number of years is;

4-1=3years

Therefore,

8360 × (1.0275)^3 =

8360 × 1.0849 = £9069.764

3 0

2 years ago

Read 2 more answers