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alex41 [277]
3 years ago
13

Please Help. Pre calc Establish the Identity : sec u +tan u =cos u/1-sin u

Mathematics
2 answers:
Tanzania [10]3 years ago
6 0

Answer:

I hope this helps    :)

Step-by-step explanation:

Mamont248 [21]3 years ago
6 0

Answer:

may be the guy is correct

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Which logarithmic equation is equivalent to 82 = 64?
34kurt

Answer: Choice B

2 = \log_{8}(64)

======================================================

Explanation:

The original equation is 8^2 = 64 with 8 as the base. That is also the base of the log when we get the final answer shown above. Logs are useful to isolate the exponent.

The general rule is that \text{y} = b^{\text{x}} is equivalent to the log form of \text{x} = \log_{b}(\text{y}) where b is the base of each.

8 0
2 years ago
Read 2 more answers
Can someone help me with part b on this question please?
Galina-37 [17]

9514 1404 393

Answer:

  12.0 cm

Step-by-step explanation:

The Pythagorean theorem applies:

  (12 cm)² +b² = (17 cm)²

  b² = (289 -144) cm² = 145 cm²

  b = √145 cm ≈ 12.04 cm

  b ≈ 12.0 cm . . . . rounded to 1 decimal place

8 0
3 years ago
What is the value of cos ø in the diagram below?<br> A. 3/5<br> B. 3/4<br> C. 4/5<br> D. 4/3
bazaltina [42]

Answer: The answer is A. 3/5

Step-by-step explanation:

Cos is the X coordinate given in parenthesis.

The X coordinate is 0.6, so find the fraction which equals 0.6.

3/5 = 0.6

3 0
3 years ago
What is 4/7 in a decimal want to know asap<br> thanks
pashok25 [27]
57% rounded. Pretty sure that's it
5 0
3 years ago
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The functions f and g are differentiable for all real numbers x. The table below gives values for the functions and their first
sertanlavr [38]

Answer:

13/9

y =-22x+32

Step-by-step explanation:

Given that the functions f and g are differentiable for all real numbers x. The table below gives values for the functions and their first derivatives at selected values of x.

x f(x) f'(x) g(x) g'(x)

1 4 -3 5 2

2 -3 -1 4 6

3 π 8 -1 4

4 -5 unknown 0 3

a) h(x) = \frac{f(x)}{g(x)} \\h'(x) = \frac{g(x)f'(x)-f(x)g'(x)}{(g(x))^2}

(using quotient rule)

Substitute 1 for x

h'(1) = \frac{g(1)f'(1)-f(1)g'(1)}{(g(1))^2}\\=\frac{9-(-4)}{9} \\=\frac{13}{9}

b) r(x) = f(x) g(x)\\r'(x) = f(x) g'(x)+g(x)f'(x)

when x =2, r(x) = r(2) = f(2) g(2) = -12

point of contact is (2,-12)

Slope of tangent =r'(2) = f(2) g'(2)+g(2)f'(2)\\=-18+(-4) \\=-22

Using point slope form, tangent is

y+12 = -22(x-2)\\y = -22x +32

7 0
4 years ago
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