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d1i1m1o1n [39]
3 years ago
12

Please answer its do in 2 hours

Mathematics
1 answer:
evablogger [386]3 years ago
3 0

Answer:

both are reciprocals

Step-by-step explanation:

15.

\frac{5}{8}\cdot \frac{16}{20}\\\\=\frac{5}{8}\cdot\frac{8}{5}=1

so they are reciprocals

17.

\frac{2}{3}\cdot\frac{12}{18}\\\\=\frac{2}{3}\cdot \frac{3}{2}=1

so they are reciprocals

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A shirt is $25.99 if the sales tax is 8.5% what will be the total cost of the shirt? Please help:)
tankabanditka [31]
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7 0
4 years ago
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The conjugate of (2+i)²/3+i, in the form of a+ib, is
goblinko [34]

Given that

(2+i)²/(3+i)

On multiplying both numerator and the denominator with (3-i) then

⇛ [(2+i)²/(3+i)]×[(3-i)/(3-i)]

⇛ [(2+i)²(3-i)]/[(3+i)(3-i)]

⇛ [(2+i)²(3-i)]/[(3²-i²)

⇛ [(2+i)²(3-i)]/(9-i²)

⇛ [(2+i)²(3-i)]/[9-(-1)]

Since ,i² = -1

⇛ [(2+i)²(3-i)]/(9+1)

⇛ [(2+i)²(3-i)]/10

⇛ [{2²+i²+2(2)(i)}(3-i)]/10

⇛ (4+i²+4i)(3-i)/10

⇛ (4-1+4i)(3-i)/10

⇛ (3+4i)(3-i)/10

⇛ (9-3i+12i-4i²)/10

⇛ (9+9i-4(-1))/10

Since, i² = -1

⇛(9+9i+4)/10

⇛(13+9i)/10

⇛ (13/10)+ i (9/10)

We know that

The conjugate of a+ib is a-ib

So,

The conjugate of (13/10)+ i (9/10) is

(13/10)-i(9/10) ⇛ (13/10)+i (-9/10)

<u>Answer:-</u>The conjugate of (13/10)+ i (9/10) is (13/10)+i (-9/10)

<em>Additional</em><em> comment</em><em>:</em>

  • The conjugate of a+ib is a-ib and
  • i = -1
  • (a+b)² = a²+2ab+b² • (a+b)(a-b)=a²-b² •(a-b)²=a²-2ab+b².
5 0
2 years ago
Factoring by grouping 12x^2+11x+2=0​
Alex_Xolod [135]

Step-by-step explanation:

(12)(2) = 24   Find 2 numbers whose product is 24 and whose sum is 11  (8 and 3 work)

 

Rewrite 11x as 8x+3x and factor by grouping:

 

12x2 + 8x + 3x + 2 = 0

 

4x(3x+2) + 1(3x+2) = 0

 

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x = -2/3 or x = -1/4

7 0
4 years ago
How do u do this I don't understand
ruslelena [56]
Use the equation y=mx+b
6 0
3 years ago
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