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3 years ago

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TJ is investing his birthday money in a savings account that pays 3% interest. If he invests $200, how much will he have at the

end of 9 months?
A. $204.50
B. 450.00
C. 245.00
D. 540.00

2 answers:

Furkat [3]3 years ago

4 0

Answer:

A. $204.50

Step-by-step explanation:

postnew [5]3 years ago

4 0

The answer to the question is A

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Que is on pic.i can't able to type in text.

ad-work [718]

It's not difficult to compute the values of $A$ and $B$ directly:

$A=\displaystyle\int_1^{\sin\theta}\frac{\mathrm dt}{1+t^2}=\tan^{-1}t\bigg|_{t=1}^{t=\sin\theta}$
$A=\tan^{-1}(\sin\theta)-\dfrac\pi4$

$B=\displaystyle\int_1^{\csc\theta}\frac{\mathrm dt}{t(1+t^2)}=\int_1^{\csc\theta}\left(\frac1t-\frac t{1+t^2}\right)\,\mathrm dt$
$B=\left(\ln|t|-\dfrac12\ln|1+t^2|\right)\bigg|_{t=1}^{t=\csc\theta}$
$B=\ln\left|\dfrac{\csc\theta}{\sqrt{1+\csc^2\theta}}\right|+\dfrac12\ln2$

Let's assume $0$ , so that $|\csc\theta|=\csc\theta$ .

Now,

$\Delta=\begin{vmatrix}A&A^2&B\\e^{A+B}&B^2&-1\\1&A^2+B^2&-1\end{vmatrix}$
$\Delta=A\begin{vmatrix}B^2&-1\\A^2+B^2&-1\end{vmatrix}-e^{A+B}\begin{vmatrix}A^2&B\\A^2+B^2&-1\end{vmatrix}+\begin{vmatrix}A^2&B\\B^2&-1\end{vmatrix}$
$\Delta=A(-B^2+A^2+B^2)-e^{A+B}(-A^2-A^2B-B^3)+(-A^2-B^3)$
$\Delta=A^3-A^2-B^3+e^{A+B}(A^2+A^2B+B^3)$

There doesn't seem to be anything interesting about this result... But all that's left to do is plug in $A$ and $B$ .

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2 years ago

Sam loaned $8,000 to his brother to make a down payment on a new home. Three

Mekhanik [1.2K]

Answer:

$1,200 interest.

Step-by-step explanation:

To use the simple interest formula, I = Prt, we substitute in the values for variables that are given, ... Do you know that banks pay you to let them keep your money? ... Find the rate if a principal of $9,000 earned $1,755 interest in 3 years. ... Five years later, she paid him back the $8,000, plus $1,200 interest.

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2 years ago

Expand and simplify (y-3)³

Tanya [424]

Answer:

Expanded: (y-3)(y-3)(y-3)

Simplified: $y^{3}-9y^{2}+27y-27$

Step-by-step explanation:

Expanded: (y-3)(y-3)(y-3)

Simplified:

$y^{2} -3y-3y+9(y-3)\\y^{2} -6y+9(y-3)$

$y^{3} -3y^{2}-6y^{2} +18y+9y-27$

$y^{3}-9y^{2} +27y-27$

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3 years ago

Perrys Bikes rents bikes for $17 plus $6 per hour. john paid $59 to rent a bike. For how many hours did he rent the bike?

matrenka [14]

7 hours

Let x represent hours rented
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3 years ago

Evaluate -4a + 10 when a = -2

stiks02 [169]

Answer:

<u>18</u>

Step-by-step explanation:

<em>replace a with -2</em>

-4(-2) + 10

<em>multiply the -4 and the -2, the negatives cancel out and leave you with 8</em>

8 +10

<em>just add</em>

18

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3 years ago