Answer:
1/18 I believe or it should be 1/3. May be wrong, sorry
To solve quadratics, the most correct and effective way, in my opinion, is the quadratic formula:
![{\displaystyle x={\frac {-b\pm {\sqrt {b^{2}-4ac}}}{2a}}.}](https://tex.z-dn.net/?f=%7B%5Cdisplaystyle%20x%3D%7B%5Cfrac%20%7B-b%5Cpm%20%7B%5Csqrt%20%7Bb%5E%7B2%7D-4ac%7D%7D%7D%7B2a%7D%7D.%7D%20)
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Plugging it in, we get:
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![\frac{-4\pm \sqrt{16+72} }{12} = \frac{-4\pm 2\sqrt{22}}{12} = \frac{-2\pm \sqrt{22} }{6}](https://tex.z-dn.net/?f=%20%5Cfrac%7B-4%5Cpm%20%5Csqrt%7B16%2B72%7D%20%7D%7B12%7D%20%20%3D%20%20%5Cfrac%7B-4%5Cpm%202%5Csqrt%7B22%7D%7D%7B12%7D%20%3D%20%20%5Cfrac%7B-2%5Cpm%20%5Csqrt%7B22%7D%20%7D%7B6%7D%20%20)
So the final answer is:
![\frac{ \sqrt{22}-2 }{6}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%5Csqrt%7B22%7D-2%20%7D%7B6%7D%20)
and
Subtract the powers
c. 9-7 so 10^2
d. 8-1 so 5^7
Answer:
-3/2
Step-by-step explanation:
this is a answer first u dived then plus