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Lisa [10]
3 years ago
12

TJ is investing his birthday money in a savings account that pays 3% interest. If he invests $200, how much will he have at the

end of 9 months?
A. $204.50
B. 450.00
C. 245.00
D. 540.00
Mathematics
2 answers:
Furkat [3]3 years ago
4 0

Answer:

A. $204.50

Step-by-step explanation:

postnew [5]3 years ago
4 0
The answer to the question is A
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IrinaVladis [17]
The second one is the answer
7 0
2 years ago
For all values of x, which expression is equivalent to 2x + 5 − x + 3x + x − 2?
koban [17]

Answer:

5x + 3

Step-by-step explanation:

1) Collect like terms.

(2x − x + 3x + x) + (5 − 2)

2) Simplify

5 x + 3

4 0
3 years ago
Read 2 more answers
Need help ASAP !!!!!!
Slav-nsk [51]

Answer:

Therefore, Point M( 1 , -2 ) is the Mid point of segment ST.  

Step-by-step explanation:

Given:

Let,

point S( x₁ , y₁) ≡ ( -1 , 1)  

point T( x₂ , y₂) ≡ (3 , -5)

Point M( x , y ) is the Mid point of segment ST.  

To Find:

Point M( x , y )= ?

Solution:

As Point M( x , y ) is the Mid point of segment ST.

So we have Mid Point Formula as

Mid\ pointM(x,y)=(\frac{x_{1}+x_{2} }{2}, \frac{y_{1}+y_{2} }{2})

On substituting the given values in above equation we get

M(x,y)=(\frac {-1+3}{2},\frac{-5+1}{2})\\\\M(x,y)=(\frac{2}{2},\frac{-4}{2}) \\\\M(x,y)=(1,-2)\ \textrm{which the required midpoint}

Therefore, Point M( 1 , -2 ) is the Mid point of segment ST.  

4 0
3 years ago
In order to compare the real estate markets in Pittsburgh and Philadelphia, a realtor selected
melisa1 [442]

Answer:

The price of the homes in the Pittsburgh sample typically vary by about $267,210 from the mean home price of $500,000.

Step-by-step explanation:

The dotplots reveal that the variability of home prices in the Pittsburgh sample is greater than the variability of home prices in the Philadelphia sample. Therefore, the standard deviation of the home prices for the Pittsburgh sample is $267,210 rather than $100,740. The correct interpretation of this statistic is that the price of homes in Pittsburgh typically vary by about $267,210 from the mean home price of $500,000.

5 0
3 years ago
Suppose a research firm conducted a survey to determine the average amount of money steady smokers spend on cigarettes during a
olchik [2.2K]

Answer:

option (b) 0.0228

Step-by-step explanation:

Data provided in the question:

Sample size, n = 100

Sample mean, μ = $20

Standard deviation, s = $5

Confidence interval = between $19 and $21

Now,

Confidence interval = μ ± z\frac{s}{\sqrt n}

thus,

Upper limit of the Confidence interval = μ + z\frac{s}{\sqrt n}

or

$21 =  $20 + z\frac{5}{\sqrt{100}}

or

z = 2

Now,

P(z = 2) = 0.02275                       [From standard z vs p value table]

or

P(z = 2) ≈ 0.0228

Hence,

the correct answer is option (b) 0.0228

3 0
3 years ago
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