Answer:
B. 5 + 7i
General Formulas and Concepts:
<u>Pre-Algebra</u>
<u>Algebra I</u>
<u>Algebra II</u>
- Complex Standard Form: a + bi
- Imaginary Numbers
Step-by-step explanation:
<u>Step 1: Define expression</u>
(8 + 9i) + (5 - 9i) - (8 - 7i)
<u>Step 2: Simplify</u>
- Distribute negative: 8 + 9i + 5 - 9i - 8 + 7i
- Combine like terms: 5 + 7i
Answer:
ΔJLK≅ ΔMLN
Step-by-step explanation:
SSS
Answer:
P(-1, 0); Q(0, -1); R(2, -1).
Step-by-step explanation:
When you reflect coordinates over the y-axis, the y-coordinates do not change, while the signs of the x-coordinates are flipped. You can see the example attached!
And so, after reflecting P'(1, 0), you would get P(-1, 0) because the sign of the x-value is flipped and the y-value does not change.
Q'(0, -1) becomes Q(0, -1) because 0 is neither negative nor positive, and the y-value does not change.
R'(-2, -1) becomes R(2, -1) because the sign of the x-value is flipped to positive and the y-value does not change.
Hope this helps!
1) 6÷0.2 = 30
If 6/2=3 then 6/0.2=30 as the decimal place shifts one place.
2)8÷0.1 = 80
8/1=8 so shift the decimal place over once to make 80.
3)9÷0.3 = 30
9/3=3 so shift the decimal place over once to get 30.
4)4÷0.04 = 100
4/4=1 so shift the decimal place over twice to get 100.
5)7÷0.002 = 3500
7/2=3.5 so shift the decimal place over three times to get 3500
6)0.718÷0.2 = 3.59
718/2=359 so shift the decimal over three places for the 0.718 and then back over once for the 0.2
7)0.0141÷0.003 = 4.7
141/3=47 so shift the decimal over our times for the 0.0141 and then back over three times for the 0.003
8)0.24÷0.012 = 20
24/12=2 so shift the decimal point over once twice for 0.24 then back over three times for 0.012
9)1.625÷0.0013 = 1250
1625/13=125 so shift the decimal point over three times for the 1.625 and then back four times for the 0.0013
10)47.1÷0.15 = 314
471/15=31.4 so shift the decimal point over once for the 47.1 and then back over twice for the 0.15.
Hope this helps :)
