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2 years ago

Rewrite y = x2 + x - 20 in factorized form.

Mathematics

2 answers:

Natalija [7]2 years ago

7 0

Answer:

y = (x + 5)(x - 4)

Step-by-step explanation:

Given

y = x² + x - 20

Consider the factors of the constant term (- 20) which sum to give the coefficient of the x- term (+ 1)

The factors are + 5 and - 4, since

5 × - 4 = - 20 and 5 - 4 = + 1, thus

x² + x - 20 = (x + 5)(x - 4)

Tcecarenko [31]2 years ago

3 0

Answer:

y = x2 + x - 20 factors into

y = (x +5) * (x -4)

Step-by-step explanation:

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Hellllllp see the pictures

kupik [55]

A. All remaining numbers are in Q because it goes "even" left, and "odd" right.

B. Probability of it not being in Q is 1/2

3 0

3 years ago

Write the cubic polynomial function f(x)in expanded form with zeros −6,−5,and −1, given that f(0)=60

RSB [31]

Answer:

$f(x)=2x^{3}+24x^{2}+82x+60$

Step-by-step explanation:

we know that

The roots of the polynomial are the values of x when the value of the polynomial f(x) is equal to zero

The roots of the polynomial function are

x=-6 -----> (x+6)=0

x=-5 -----> (x+5)=0

x=-1 -----> (x+1)=0

The equation of the cubic polynomial is

$f(x)=a(x+6)(x+5)(x+1)$

where

a is the leading coefficient

Remember that

f(0)=60

That means ------> For x=0 the value of f(x) is equal to 60

substitute the value of x and the value of y in the function and solve for a

$60=a(0+6)(0+5)(0+1)$

$60=a(6)(5)(1)$

$60=30a$

$a=2$

$f(x)=2(x+6)(x+5)(x+1)$

Applying the distributive property

Convert to expanded form

$f(x)=2(x+6)(x+5)(x+1)\\\\f(x)=2(x+6)(x^{2}+x+5x+5)\\\\f(x)=2(x+6)(x^{2}+6x+5)\\\\f(x)=2(x^{3}+6x^{2}+5x+6x^{2}+36x+30)\\\\f(x)=2x^{3}+24x^{2}+82x+60$

3 0

3 years ago

Order from least to greatest 61% , 0.605, 3/5, 59%

krek1111 [17]

So you'd have to convert all of the values to one form, and I find it easiest to do it in decimals. 61% would be 0.61, 0.605 stays the same, 3/5 would be 0.6, and 59% would be 0.59. Now you can order them:
0.59, 0.6, 0.605, 0.61
You have to convert them back to their original form, however, so your answer would be
59%, 3/5, 0.605, 61%
I hope this helps!

6 0

3 years ago

Read 2 more answers

For the following pair of functions, find (f+g)(x) and (f-g)(x).

ch4aika [34]

Given:

The functions are

$f(x)=4x^2+7x-5$

$g(x)=-9x^2+4x-13$

To find:

The functions $(f+g)(x)$ and $(f-g)(x)$ .

Solution:

We know that,

$(f+g)(x)=f(x)+g(x)$

$(f+g)(x)=4x^2+7x-5-9x^2+4x-13$

$(f+g)(x)=(4x^2-9x^2)+(7x+4x)+(-5-13)$

$(f+g)(x)=-5x^2+11x-18$

And,

$(f-g)(x)=f(x)-g(x)$

$(f-g)(x)=(4x^2+7x-5)-(-9x^2+4x-13)$

$(f+g)(x)=4x^2+7x-5+9x^2-4x+13$

$(f+g)(x)=(4x^2+9x^2)+(7x-4x)+(-5+13)$

$(f-g)(x)=13x^2+3x+8$

Therefore, the required functions are $(f+g)(x)=-5x^2+11x-18$

and $(f-g)(x)=13x^2+3x+8$ .

7 0

3 years ago

You originally draw a design for an art contest on a 2 inch by 5 inch card. The second phrase of the contest requires the drawin

Bingel [31]

4.2.
If the 2 inch side was scaled to 10.5 inches the 5 inch side would be scaled by 10.5/2 = 5.25, so would be 25.125 inches which is too big.

So the 10.5 inches is the 5 inch side on the original, and so it 10.5/5 = 2.1 times bigger.

Therefore the smaller side would be 2*2.1/= 4.2 inches.

4 0

3 years ago