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vivado [14]
3 years ago
12

Hannah factored the expression 24xy + 15y. Her work is shown below.

Mathematics
2 answers:
Evgesh-ka [11]3 years ago
6 0

Answer:

the top is the right answer

Step-by-step explanation:

Cloud [144]3 years ago
4 0

the correct answer on edge is;

a. she divided by 3 instead of the GCF.

d. she didn’t complete step 4 and use the distributive property to be sure the expressions are equivalent.

e. she didn’t undistribute the GCF from the original expression.

welcome!

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Find the rang of the data 81 78 74 88 73 76 93 98 78 80
Makovka662 [10]
Range = highest number - smallest number
= 98- 73
= 25
8 0
4 years ago
What would make this a parallelogram
Helen [10]
All 4 sides are parrell
4 0
4 years ago
Last school year, the student body of a local university consisted of 30% freshmen, 24% sophomores, 26% juniors, and 20% seniors
tino4ka555 [31]

Answer:

\chi^2 = \frac{(83-90)^2}{90} +\frac{(68-72)^2}{72}+\frac{(85-78)^2}{78}+\frac{(64-60)^2}{60} = 1.66

And the answer would be:

c. 1.66

Step-by-step explanation:

We need to conduct a chi square test

The statistic to check the hypothesis is given by:

\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

the observed values for this case are:

Freshemen=83

Sophomores=68

Juniors = 85

Seniors= 64

The expected values for this case are:

Fres_E =0.3*300= 90

Sop_E =0.24*300= 72

Jun_E = 0.26*300 =78

Sen_E = 0.20*300= 60

Then the statistic would be given by:

\chi^2 = \frac{(83-90)^2}{90} +\frac{(68-72)^2}{72}+\frac{(85-78)^2}{78}+\frac{(64-60)^2}{60} = 1.66

And the answer would be:

c. 1.66

4 0
4 years ago
5x^{2}<br> <img src="https://tex.z-dn.net/?f=5x%5E%7B2%7D" id="TexFormula1" title="5x^{2}" alt="5x^{2}" align="absmiddle" class=
madreJ [45]

Step-by-step explanation:

{5}^{2}  = 25

7 0
3 years ago
Read 2 more answers
A principal of $3400 is invested at 7.75% interest, compounded annually. How much will the investment be worth after 15 years? U
DENIUS [597]
A = $ value after 15 years
P = principal (initial deposit)
r = annual % rate
n = # of times interest compounds per year
t = # of years the money is invested

Formula:
A = P (1 + r/n)^(nt)

A= $3400(1+ 0.0775/1) ^(1*15)
A= 3400(1.0775)^15
A= 3400(3.0637913274)
A= $10,417 investment after 15 years

Hope this helps! :)
4 0
3 years ago
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