<h3>
Answer: B) Only the first equation is an identity</h3>
========================
I'm using x in place of theta. For each equation, I'm only altering the left hand side.
Part 1
cos(270+x) = sin(x)
cos(270)cos(x) - sin(270)sin(x) = sin(x)
0*cos(x) - (-1)*sin(x) = sin(x)
0 + sin(x) = sin(x)
sin(x) = sin(x) ... equation is true
Identity is confirmed
---------------------------------
Part 2
sin(270+x) = -sin(x)
sin(270)cos(x) + cos(270)sin(x) = -sin(x)
-1*cos(x) + 0*sin(x) = -sin(x)
-cos(x) = -sin(x)
We don't have an identity. If the right hand side was -cos(x), instead of -sin(x), then we would have an identity.
Answer:
I guess you want the y intercept form is so the answer is:
y = 
x - 4
Step-by-step explanation:
3x - 2y = 8
subtract 3x from both sides
-2y = -3x + 8
divide -2 from both sides
y = x - 4
and done
Answer:
yes
Step-by-step explanation:
X^(1/7)x^(1/7)x^(1/7)x^(1/7)
Well the rule for multiplying similar bases with exponents is:
(a^b)(a^c)(a^d)=a^(b+c+d), so in this case:
x^(1/7+1/7+1/7+1/7)
x^(4/7)
In words that is x raised to the 4/7 th power or the seventh root of x raised to the 4th power.
