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enyata [817]
3 years ago
15

Is 0.045 greater than 0.00195​

Mathematics
1 answer:
andrezito [222]3 years ago
4 0

Answer:

yes

Step-by-step explanation:

0.045 is greater than 0.00195

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Factor b3 +b2 + b + 1.
olga nikolaevna [1]

Answer:

(b+1)(b²+1)

Step-by-step explanation:

8 0
3 years ago
PLEASE HELP FAST!!<br> Will mark brainlest!!
Elina [12.6K]
We can’t see it clearly
4 0
3 years ago
It takes 54 minutes for 4 people to paint 6 walls. How many minuets does it take 6 people to paint 7 walls?
earnstyle [38]

It takes 42 minutes for 6 people to paint 7 walls

<em><u>Solution:</u></em>

It takes 54 minutes for 4 people to paint 6 walls

To find: Minutes required for 6 people to paint 7 walls

If M_1 men can do W_1 work in D_1 days working H_1 hours per day and M_2 men can do W_2 work in D_2 days working H_2 hours per day, then

\frac{M_1D_1H_1}{W_1} = \frac{M_2D_2H_2}{W_2}

M = Number of men

D = Number of days

H = Number of hours per day

W = Amount of work

Here in this sum,

<em><u>54 minutes for 4 people to paint 6 walls</u></em>

H_1 = 54 minutes ; M_1 = 4 people ; W_1 = 6 walls

<em><u>Minutes required for 6 people to paint 7 walls</u></em>

H_2 = ? ; M_2 = 6 people ; W_2 = 7 walls

<em><u>Substituting the values in formula, we get</u></em>

\frac{54 \times 4}{6} = \frac{H_2 \times 6}{7}\\\\9 \times 4 = \frac{H_2 \times 6}{7}\\\\H_2 = \frac{36 \times 7}{6}\\\\H_2 = 42

Thus it takes 42 minutes for 6 people to paint 7 walls

7 0
4 years ago
Find the value of kk for which the constant function x(t)=kx(t)=k is a solution of the differential equation 5t3dxdt+2x−2=05t3dx
uranmaximum [27]
Given the differential equation

5t^3 \frac{dx}{dt} +2x-2=0

The solution is as follows:

5t^3 \frac{dx}{dt} +2x-2=0 \\  \\ \Rightarrow5t^3 \frac{dx}{dt} =2-2x \\  \\ \Rightarrow \frac{5}{2-2x} dx= \frac{1}{t^3} dt \\  \\ \Rightarrow \int {\frac{5}{2-2x} } \, dx = \int {\frac{1}{t^3}} \, dt \\  \\ \Rightarrow- \frac{5}{2} \ln(2-2x)=- \frac{1}{2t^2} +A \\  \\ \Rightarrow\ln(2-2x)= \frac{1}{5t^2} +B\\  \\ \Rightarrow2-2x=Ce^{\frac{1}{5t^2}} \\  \\ \Rightarrow 2x=Ce^{\frac{1}{5t^2}}+2 \\  \\ \Rightarrow x=De^{\frac{1}{5t^2}}+1
3 0
3 years ago
The data set represents a progression of hourly temperature measurements.Use the regression equation to predict the temperature
zimovet [89]
I will attach google sheet that I used to find regression equation.
We can see that linear fit does work, but the polynomial fit is much better.
We can see that R squared for polynomial fit is higher than R squared for the linear fit. This tells us that polynomials fit approximates our dataset better.
This is the polynomial fit equation:
T(h)=20.2-3.6h-0.875h^2
I used h to denote hours. Our prediction of temperature for the sixth hour would be:
T(6)=20.2-3.6(6)-0.875(6)^2=-32.9
Here is a link to the spreadsheet  (<span>https://docs.google.com/spreadsheets/d/17awPz5U8Kr-ZnAAtastV-bnvoKG5zZyL3rRFC9JqVjM/edit?usp=sharing)</span>

4 0
3 years ago
Read 2 more answers
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