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hram777 [196]
2 years ago
14

3 x. 3x²+x-3=0 Find the zeros

Mathematics
1 answer:
Tanya [424]2 years ago
3 0

Answer:

The zeroes of this polynomial are x_{1} \approx 0.847 and x_{2} \approx -1.180.

Step-by-step explanation:

Let 3\cdot x^{2}+x - 3 = 0, the quickest and most efficient approach to find the zeroes of this second order polynomial is by Quadratic Formula. For all a\cdot x^{2}+b\cdot x + c = 0, roots are determined by:

x_{1,2} = \frac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a} (1)

Where a, b, c are coefficients of the polynomial.

If we know that a = 3, b = 1 and c = -3, then roots of the polynomial are, respectively:

x_{1,2} = \frac{-1\pm\sqrt{1^{2}-4\cdot (3)\cdot (-3)}}{2\cdot (3)}

x_{1,2} =\frac{-1\pm \sqrt{37}}{6}

The zeroes of this polynomial are x_{1} \approx 0.847 and x_{2} \approx -1.180.

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