The function is written as:
f(x) = log(-20x + 12√x)
To find the maximum value, differentiate the equation in terms of x, then equate it to zero. The solution is as follows.
The formula for differentiation would be:
d(log u)/dx = du/u ln(10)
Thus,
d/dx = (-20 + 6/√x)/(-20x + 12√x)(ln 10) = 0
-20 + 6/√x = 0
6/√x = 20
x = (6/20)² = 9/100
Thus,
f(x) = log(-20(9/100)+ 12√(9/100)) = 0.2553
<em>The maximum value of the function is 0.2553.</em>
Answer:
one to one function
Step-by-step explanation:
f(x)=6x+1 can only be a one to one function when x1=x2
Now,
f(x1)=f(x2)
or, 6x1 + 1 = 6x2 + 1
or, 6x1 = 6x2
or, x1 = x2
So f(x)= 6x + 1 is a one to one function
Let's solve ~
Therefore, the lateral surface area of cone = 180 pi in²
➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖
One and seventy-five thousandths
