50 POINTS - A Builder intends placing 7 equally spaced homes on a semicircular plot. If the circle has a diameter of 400 feet, w
hat is the distance between any two adjacent homes
1 answer:
Answer: 89.7 ft
<u>Step-by-step explanation:</u>
Find the arc length (s) of the semi-circle. Then divide that length by 7.
s = r · θ where r is the radius and θ is the angle in radians
s = (400 ÷ 2) · π <em>(radius is diameter divided by 2)</em>
= 200π
= 628.3
The length of the arc is 628.3 ft. Divide that by 7 to find the distance between each home.
628.3 ÷ 7 = 89.7
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