Question

50 POINTS - A Builder intends placing 7 equally spaced homes on a semicircular plot. If the circle has a diameter of 400 feet, what is the distance between any two adjacent homes

Answer 1

Answer:  89.7 ft

Step-by-step explanation:

Find the arc length (s) of the semi-circle.  Then divide that length by 7.

s = r · θ      where r is the radius and θ is the angle in radians

s = (400 ÷ 2) · π        (radius is diameter divided by 2)

  = 200π

  = 628.3

The length of the arc is 628.3 ft.  Divide that by 7 to find the distance between each home.

628.3 ÷ 7 = 89.7