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Maksim231197 [3]
3 years ago
10

How can a solution to a system of linear equations be determined exactly by graphing?

Mathematics
1 answer:
givi [52]3 years ago
5 0
A solution something something and that’s the answer
You might be interested in
A student desired to invest $1,540 into an investment at 9% compounded semiannually for 6 years. With all else equal, what is th
irga5000 [103]

Answer:

The future value of this initial investment after the six year period is $2611.6552

Step-by-step explanation:

Consider the provided information.

A student desired to invest $1,540 into an investment at 9% compounded semiannually for 6 years.

Future value of an investment: FV=P(1+r)^n

Where Fv is the future value, p is the present value, r is the rate and n is the number of compounding periods.

9% compounded semiannually for 6 years.

Therefore, the value of r is: r=\frac{0.09}{2}=0.045

Number of periods are: 2 × 6 = 12

Now substitute the respective values in the above formula.

FV=1540(1+0.045)^{12}

FV=1540(1.045)^{12}

FV=1540(1.69588)

FV=2611.6552

Hence, the future value of this initial investment after the six year period is $2611.6552

6 0
3 years ago
Can anyone please answer these for me?
yulyashka [42]

11.  y=-3x-5

12.  y=-5

13. y= -1/3x+5

14.  y=3x-5

3 0
3 years ago
Find the surface area of the cylinder in terms of Tt
sveta [45]

Answer:

140 π cm^2

HOPE THIS HELPS! :)

5 0
2 years ago
Read 2 more answers
Show work on how you converted them. (also marking brainliest) <3
Dmitry_Shevchenko [17]

Answer:

1. 5700mg

2. 1000cm

3. 0.0453m

4. 37.5 kg/L

Step-by-step explanation:

1. 1gram (g) =1000milligrams(mg)

5.70×1000=5700mg

2. 1 m= 100cm

10×100=1000cm

3. 1000mm=1m

45.3/1000=0.0453m

4. 1000g=1kg

37.5/1000=0.0375

1000ml=1L

1ml= 1/1000= 0.001L

0.0375/0.001= 37.5 kg/L

8 0
3 years ago
Help???????????????????????????????????????????????????
julsineya [31]

Answer:

First option is the correct choice.

Step-by-step explanation:

y - Q = 3(x - P)

3P - Q = 3x - y

Best Regards!

5 0
3 years ago
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