Answer:
(53.812 ; 58.188) ; 156
Step-by-step explanation:
Given that :
Sample size (n) = 51
Mean (m) = 56
Standard deviation (σ) = 9.5
α = 90%
Using the relation :
Confidence interval = mean ± Error
Error = Zcritical * (standard deviation / sqrt (n))
Zcritical at 90% = 1.645
Error = 1.645 * (9.5 / sqrt(51))
Error = 1.645 * 1.3302660
Error = 2.1882877
Hence,
Confidence interval :
Lower boundary = 56 - 2.1882877 = 53.8117123
Upper boundary = 56 + 2.1882877 = 58.1882877
Confidence interval = (53.812 ; 58.188)
2.)
Margin of Error (ME) = 1.25
α = 90%
Sample size = ((Zcritical * σ) / ME)^2
Zcritical at 90% = 1.645
Sample size = ((1.645 * 9.5) / 1.25)^2
Sample size = (15.6275 / 1.25)^2
Sample size = 12.502^2 = 156.3000
Sample size = 156
Answer:
-60x+20 = -400
x equals 7
Step-by-step explanation:
12x - 4x = 8 + 3 - 3
8x = 8
X = 1
Answer: D
Step-by-step explanation:
it equals 15/12
Let us assume the number of movies for ehich the cost of both companies becomes the same = x
Then
55 + 4x = 110
4x = 110 - 55
4x = 55
x = 55/4
= 13.75
So
The number <span>number of movies for which the cost of Carl's cable company is less than the cost of Teleview = 13.
I hope the procedure is clear enough for you to understand and this is the answer that you were actually looking for.</span>
