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Morgarella [4.7K]
3 years ago
8

What is the exact distance from (−4, −2) to (4, 6)?

Mathematics
1 answer:
PIT_PIT [208]3 years ago
8 0
Hopefully this is right :)

You might be interested in
Solve for x: 2 over 3 equals the quantity x minus 1 end quantity over 5
sweet-ann [11.9K]

Answer:

13 over 3

Step-by-step explanation:

Hi Jakeyriabryant! I hope you’re fine!

I hope I have understood the problem well.

If so, what the exercise raises is the following equality:

(x-1) / 5 = 2/3

From this equation you must clear the "x".

First, we pass the 5 that is dividing on the side of the x, to the other side and passes multiplying

(X – 1) / 5 = 2/3  

(X – 1) = (2/3)*5

X – 1 = 10/3

Then we pass the one that is subtracting from the side of the x, to the other side and passes adding

X  = 10/3 + 1

Remember that to add or subtract fractions they must have the same denominator or a common denominator (in this case we can write 1 as fraction 3/3). Then,

X = 10/3 + 3/3

X = 13/3

I hope I've been helpful!

Regards!

7 0
3 years ago
Use elimination to solve the system of equations.<br><br> 3x – 5y = –9<br> x + 2y = 8
nalin [4]

Answer:

x=2

y=3

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
How do u convert a fraction into a decimal
lesya692 [45]
You have to divide the numerator (top number) by the denominator (bottom number). For example, 1/2 is 0.5
However, some end up as never-ending decimals, like 1/3, which converts to 0.333 repeating.
3 0
3 years ago
What does a cop never forget to say
Kruka [31]
Probably they never forget to give the Miranda warning.
8 0
3 years ago
Please. Answer Fast! Use composition to determine if G(x) or H(x) is the inverse of F(x) for the
s344n2d4d5 [400]

Answer:

A. H(x) is an inverse of F(x)

Step-by-step explanation:

The given functions are:

F(x)=\sqrt{x-2}

G(x)=(x-2)^2

H(x)=x^2+2

We compose F(x) and G(x) to get:

(F\circ G)(x)=F(G(x))

(F\circ G)(x)=F((x-2)^2)

(F\circ G)(x)=\sqrt{(x-2)^2-2}

(F\circ G)(x)=\sqrt{x^2-4x+4-2}

(F\circ G)(x)=\sqrt{x^2-4x+2}

(F\circ G)(x)\ne x

Hence G(x) is not an inverse of F(x).

We now compose H(x) and G(x).

(F\circ H)(x)=F(H(x))

(F\circ H)(x)=F(x^2+2)

(F\circ H)(x)=\sqrt{x^2+2-2}

We simplify to get:

(F\circ H)(x)=\sqrt{x^2}

(F\circ H)(x)=x

Since (F\circ H)(x)=x, H(x) is an inverse of F(x)

3 0
3 years ago
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