Answer:
144
Step-by-step explanation:
On this shape we are going to splt up the 4 triangles for the square to make it simple.
So, firstly, plug is the h an w of one of the triangles into the formula for the area of a triangle which is hxw/2
H=9
W=6
9x6/2=27
Then multiply the area of the triangle, 27, to get the total area of all 4 triangles (since they all have the same measurements)
27x4=108
108 is the area of all 4 triangles
Next, just put the l and w into the equation for the area of a square which is lxw
L=6
W=6
6x6=36
36 is the area of the square
Lastly, just add the areas of the triangles and the square together
108+36=144
144 is the total area/surface area, of the pyramid
Answer:
IJ = 34
Step-by-step explanation:
Since HK = JK, then IK is a perpendicular bisector and Δ is isosceles, then
IJ = HI , that is
2s = s + 17 ( subtract s from both sides )
s = 17
Then
IJ = 2s = 2 × 17 = 34
The side length is the square root of 8. Because the square has 4 equal sides, the side lengths must be equal. So the answer is approximately 2.83.
