I'm pretty sure it would be C
because 0.17 is how much he has to pay for each message sent and if x is the total messages he sends then it should be 0.17X+24.07
Recognize that "( ) over 2^3" means ( ) • 2^-3. Use the rule of exponents
.. (a^b)^c = a^(b•c)
= 2^-16•5^10•19^-2 • 5^-8*2^-12 • 2^28
Now, you can use the rule of exponents
.. (a^b)*(a^c) = a^(b+c)
= 2^(-16 -12 +28) • 5^(10 -8) • 19^-2
= 5^2 • 19^-2
= 5^2 / 19^2
= 25/361
4jnirfioensorrrrrrrrrrious
Solve <span>3x+2y-6=0 for y
2y-6=-3x
2y=-3x+6
y=-1.5x+3
So the slope of the reference line is -1.5. For two lines to be parallel they must have the same slope so our line will also have a slope of -1.5 so we have:
y=-1.5x+b, now we can solve for b given the point (0,0)
0=-1.5(0)+b
0=0+b
b=0 so our line is:
y=-1.5x</span>
Answer:
5. 8
6. 18
Step-by-step explanation:
5.
a(a^2 + a - 1) + 7 =
= a^3 + a^2 - a + 7
For a = -1,
= (-1)^3 + (-1)^2 - (-1) + 7
= -1 + 1 + 1 + 7
= 8
6.
2ab(a + b) - 3ab(a - b) =
= 2a^2b + 2ab^2 - 3a^2b + 3ab^2
= -a^2b + 5ab^2
For a = 1 and b = 2,
= -(1)^2(2) + 5(1)(2)^2
= -1(2) + 5(4)
= - 2 + 20
= 18
